Last Updated on August 27, 2020

The Keras library provides a way to calculate and report on a suite of standard metrics when training deep learning models.

In addition to offering standard metrics for classification and regression problems, Keras also allows you to define and report on your own custom metrics when training deep learning models. This is particularly useful if you want to keep track of a performance measure that better captures the skill of your model during training.

In this tutorial, you will discover how to use the built-in metrics and how to define and use your own metrics when training deep learning models in Keras.

After completing this tutorial, you will know:

- How Keras metrics work and how you can use them when training your models.
- How to use regression and classification metrics in Keras with worked examples.
- How to define and use your own custom metric in Keras with a worked example.

**Kick-start your project** with my new book Deep Learning With Python, including *step-by-step tutorials* and the *Python source code* files for all examples.

Let’s get started.

**Update Jan/2020**: Updated API for Keras 2.3 and TensorFlow 2.0.

## Tutorial Overview

This tutorial is divided into 4 parts; they are:

- Keras Metrics
- Keras Regression Metrics
- Keras Classification Metrics
- Custom Metrics in Keras

## Keras Metrics

Keras allows you to list the metrics to monitor during the training of your model.

You can do this by specifying the “*metrics*” argument and providing a list of function names (or function name aliases) to the *compile()* function on your model.

For example:

1 |
model.compile(..., metrics=['mse']) |

The specific metrics that you list can be the names of Keras functions (like *mean_squared_error*) or string aliases for those functions (like ‘*mse*‘).

Metric values are recorded at the end of each epoch on the training dataset. If a validation dataset is also provided, then the metric recorded is also calculated for the validation dataset.

All metrics are reported in verbose output and in the history object returned from calling the *fit()* function. In both cases, the name of the metric function is used as the key for the metric values. In the case of metrics for the validation dataset, the “*val_*” prefix is added to the key.

Both loss functions and explicitly defined Keras metrics can be used as training metrics.

## Keras Regression Metrics

Below is a list of the metrics that you can use in Keras on regression problems.

**Mean Squared Error**: mean_squared_error, MSE or mse**Mean Absolute Error**: mean_absolute_error, MAE, mae**Mean Absolute Percentage Error**: mean_absolute_percentage_error, MAPE, mape**Cosine Proximity**: cosine_proximity, cosine

The example below demonstrates these 4 built-in regression metrics on a simple contrived regression problem.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 |
from numpy import array from keras.models import Sequential from keras.layers import Dense from matplotlib import pyplot # prepare sequence X = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) # create model model = Sequential() model.add(Dense(2, input_dim=1)) model.add(Dense(1)) model.compile(loss='mse', optimizer='adam', metrics=['mse', 'mae', 'mape', 'cosine']) # train model history = model.fit(X, X, epochs=500, batch_size=len(X), verbose=2) # plot metrics pyplot.plot(history.history['mean_squared_error']) pyplot.plot(history.history['mean_absolute_error']) pyplot.plot(history.history['mean_absolute_percentage_error']) pyplot.plot(history.history['cosine_proximity']) pyplot.show() |

**Note**: Your results may vary given the stochastic nature of the algorithm or evaluation procedure, or differences in numerical precision. Consider running the example a few times and compare the average outcome.

Running the example prints the metric values at the end of each epoch.

1 2 3 4 5 6 7 8 9 10 11 |
... Epoch 96/100 0s - loss: 1.0596e-04 - mean_squared_error: 1.0596e-04 - mean_absolute_error: 0.0088 - mean_absolute_percentage_error: 3.5611 - cosine_proximity: -1.0000e+00 Epoch 97/100 0s - loss: 1.0354e-04 - mean_squared_error: 1.0354e-04 - mean_absolute_error: 0.0087 - mean_absolute_percentage_error: 3.5178 - cosine_proximity: -1.0000e+00 Epoch 98/100 0s - loss: 1.0116e-04 - mean_squared_error: 1.0116e-04 - mean_absolute_error: 0.0086 - mean_absolute_percentage_error: 3.4738 - cosine_proximity: -1.0000e+00 Epoch 99/100 0s - loss: 9.8820e-05 - mean_squared_error: 9.8820e-05 - mean_absolute_error: 0.0085 - mean_absolute_percentage_error: 3.4294 - cosine_proximity: -1.0000e+00 Epoch 100/100 0s - loss: 9.6515e-05 - mean_squared_error: 9.6515e-05 - mean_absolute_error: 0.0084 - mean_absolute_percentage_error: 3.3847 - cosine_proximity: -1.0000e+00 |

A line plot of the 4 metrics over the training epochs is then created.

Note that the metrics were specified using string alias values [‘*mse*‘, ‘*mae*‘, ‘*mape*‘, ‘*cosine*‘] and were referenced as key values on the history object using their expanded function name.

We could also specify the metrics using their expanded name, as follows:

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model.compile(loss='mse', optimizer='adam', metrics=['mean_squared_error', 'mean_absolute_error', 'mean_absolute_percentage_error', 'cosine_proximity']) |

We can also specify the function names directly if they are imported into the script.

1 2 |
from keras import metrics model.compile(loss='mse', optimizer='adam', metrics=[metrics.mean_squared_error, metrics.mean_absolute_error, metrics.mean_absolute_percentage_error, metrics.cosine_proximity]) |

You can also use the loss functions as metrics.

For example, you could use the Mean squared Logarithmic Error (*mean_squared_logarithmic_error*, *MSLE* or *msle*) loss function as a metric as follows:

1 |
model.compile(loss='mse', optimizer='adam', metrics=['msle']) |

## Keras Classification Metrics

Below is a list of the metrics that you can use in Keras on classification problems.

**Binary Accuracy**: binary_accuracy, acc**Categorical Accuracy**: categorical_accuracy, acc**Sparse Categorical Accuracy**: sparse_categorical_accuracy**Top k Categorical Accuracy**: top_k_categorical_accuracy (requires you specify a k parameter)**Sparse Top k Categorical Accuracy**: sparse_top_k_categorical_accuracy (requires you specify a k parameter)

Accuracy is special.

Regardless of whether your problem is a binary or multi-class classification problem, you can specify the ‘*accuracy*‘ metric to report on accuracy.

Below is an example of a binary classification problem with the built-in accuracy metric demonstrated.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 |
from numpy import array from keras.models import Sequential from keras.layers import Dense from matplotlib import pyplot # prepare sequence X = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) y = array([0, 0, 0, 0, 0, 1, 1, 1, 1, 1]) # create model model = Sequential() model.add(Dense(2, input_dim=1)) model.add(Dense(1, activation='sigmoid')) model.compile(loss='binary_crossentropy', optimizer='adam', metrics=['accuracy']) # train model history = model.fit(X, y, epochs=400, batch_size=len(X), verbose=2) # plot metrics pyplot.plot(history.history['accuracy']) pyplot.show() |

**Note**: Your results may vary given the stochastic nature of the algorithm or evaluation procedure, or differences in numerical precision. Consider running the example a few times and compare the average outcome.

Running the example reports the accuracy at the end of each training epoch.

1 2 3 4 5 6 7 8 9 10 11 |
... Epoch 396/400 0s - loss: 0.5934 - acc: 0.9000 Epoch 397/400 0s - loss: 0.5932 - acc: 0.9000 Epoch 398/400 0s - loss: 0.5930 - acc: 0.9000 Epoch 399/400 0s - loss: 0.5927 - acc: 0.9000 Epoch 400/400 0s - loss: 0.5925 - acc: 0.9000 |

A line plot of accuracy over epoch is created.

## Custom Metrics in Keras

You can also define your own metrics and specify the function name in the list of functions for the “*metrics*” argument when calling the *compile()* function.

A metric I often like to keep track of is Root Mean Square Error, or RMSE.

You can get an idea of how to write a custom metric by examining the code for an existing metric.

For example, below is the code for the mean_squared_error loss function and metric in Keras.

1 2 |
def mean_squared_error(y_true, y_pred): return K.mean(K.square(y_pred - y_true), axis=-1) |

K is the backend used by Keras.

From this example and other examples of loss functions and metrics, the approach is to use standard math functions on the backend to calculate the metric of interest.

For example, we can write a custom metric to calculate RMSE as follows:

1 2 3 4 |
from keras import backend def rmse(y_true, y_pred): return backend.sqrt(backend.mean(backend.square(y_pred - y_true), axis=-1)) |

You can see the function is the same code as MSE with the addition of the *sqrt()* wrapping the result.

We can test this in our regression example as follows. Note that we simply list the function name directly rather than providing it as a string or alias for Keras to resolve.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 |
from numpy import array from keras.models import Sequential from keras.layers import Dense from matplotlib import pyplot from keras import backend def rmse(y_true, y_pred): return backend.sqrt(backend.mean(backend.square(y_pred - y_true), axis=-1)) # prepare sequence X = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) # create model model = Sequential() model.add(Dense(2, input_dim=1, activation='relu')) model.add(Dense(1)) model.compile(loss='mse', optimizer='adam', metrics=[rmse]) # train model history = model.fit(X, X, epochs=500, batch_size=len(X), verbose=2) # plot metrics pyplot.plot(history.history['rmse']) pyplot.show() |

**Note**: Your results may vary given the stochastic nature of the algorithm or evaluation procedure, or differences in numerical precision. Consider running the example a few times and compare the average outcome.

Running the example reports the custom RMSE metric at the end of each training epoch.

1 2 3 4 5 6 7 8 9 10 11 |
... Epoch 496/500 0s - loss: 1.2992e-06 - rmse: 9.7909e-04 Epoch 497/500 0s - loss: 1.2681e-06 - rmse: 9.6731e-04 Epoch 498/500 0s - loss: 1.2377e-06 - rmse: 9.5562e-04 Epoch 499/500 0s - loss: 1.2079e-06 - rmse: 9.4403e-04 Epoch 500/500 0s - loss: 1.1788e-06 - rmse: 9.3261e-04 |

At the end of the run, a line plot of the custom RMSE metric is created.

Your custom metric function must operate on Keras internal data structures that may be different depending on the backend used (e.g. *tensorflow.python.framework.ops.Tensor* when using tensorflow) rather than the raw yhat and y values directly.

For this reason, I would recommend using the backend math functions wherever possible for consistency and execution speed.

## Further Reading

This section provides more resources on the topic if you are looking go deeper.

- Keras Metrics API documentation
- Keras Metrics Source Code
- Keras Loss API documentation
- Keras Loss Source Code

## Summary

In this tutorial, you discovered how to use Keras metrics when training your deep learning models.

Specifically, you learned:

- How Keras metrics works and how you configure your models to report on metrics during training.
- How to use classification and regression metrics built into Keras.
- How to define and report on your own custom metrics efficiently while training your deep learning models.

Do you have any questions?

Ask your questions in the comments below and I will do my best to answer.

Off topic but interesting none the less :

1) how to train an ensemble of models in the same time it takes to train 1

http://www.kdnuggets.com/2017/08/train-deep-learning-faster-snapshot-ensembling.html

2) when not to use deep learning

http://www.kdnuggets.com/2017/07/when-not-use-deep-learning.html

Thanks for sharing.

Hi Jason,

Thanks again for another great topic on keras but I’m a R user !

I can work with keras on R, but how about to implement custom metric ‘rmse’ on keras R please ?

Because I find something like that on the github repository :

metric_mean_squared_error <- function(y_true, y_pred) {

keras$metrics$mean_squared_error(y_true, y_pred)

}

attr(metric_mean_squared_error, "py_function_name") <- "mean_squared_error"

and my poor

rmse <- function(y_true, y_pred) {

K$sqrt(K$mean(K$square(y_pred – y_true)))

}

is not working ("nan" is returned)

Ok finally I make it return a value different from ‘nan’, but the result is not the same as the square root of ‘mse’ from keras ?!? Maybe due to the arg ‘axis = -1’ ?

Sorry, I have not used Keras in R, I don’t have good advice for you at this stage.

hi Jason,

Thanks for your very good topic on evaluation metrics in keras. can you please tell me how to compute macro-F and the micro-F scores?

thanks in advance

Sorry, I am not familiar with those scores John.

Perhaps find a definition and code them yourself?

Have you considered using the scikit-learn’s implementations? https://scikit-learn.org/stable/modules/generated/sklearn.metrics.f1_score.html

Or would these not work with tensorflow?

See here:

https://machinelearningmastery.com/how-to-calculate-precision-recall-f1-and-more-for-deep-learning-models/

Hi Jason,

I used your “def rmse” in my code, but it returns the same result of mse.

# define data and target value

X = TFIDF_Array

Y = df[‘Shrinkage’]

# custom metric to calculate RMSE

def RMSE(y_true, y_pred):

return backend.sqrt(backend.mean(backend.square(y_pred – y_true), axis=-1))

# define base model

def regression_model():

# create model

model = Sequential()

model.add(Dense(512, input_dim=X.shape[1], kernel_initializer=’uniform’, activation=’relu’))

model.add(Dropout(0.5))

model.add(Dense(1, kernel_initializer=’uniform’))

# compile model

model.compile(loss=’mse’, optimizer=’sgd’, metrics=[RMSE])

return model

# evaluate model

estimator = KerasRegressor(build_fn=regression_model, nb_epoch=100, batch_size=32, verbose=0)

kfold = KFold(n_splits=3, random_state=1)

reg_results = cross_val_score(estimator, X, Y, cv=kfold)

Did the example in the post – copied exactly – work for you?

Epoch 496/500

0s – loss: 3.9225e-04 – rmse: 0.0170

Epoch 497/500

0s – loss: 3.8870e-04 – rmse: 0.0169

Epoch 498/500

0s – loss: 3.8518e-04 – rmse: 0.0169

Epoch 499/500

0s – loss: 3.8169e-04 – rmse: 0.0168

Epoch 500/500

0s – loss: 3.7821e-04 – rmse: 0.0167

It gave back different values from yours.

Epoch 497/500

0s – loss: 0.0198 – mean_squared_error: 0.0198

Epoch 498/500

0s – loss: 0.0197 – mean_squared_error: 0.0197

Epoch 499/500

0s – loss: 0.0197 – mean_squared_error: 0.0197

Epoch 500/500

0s – loss: 0.0196 – mean_squared_error: 0.0196

and these were the result when I used:

metrics=[‘mean_squared_error’]

I didn’t see any difference of MSE and RMSE here.

Please advise. Thanks.

Yes, this is to be expected. Machine learning algorithms are stochastic meaning that the same algorithm on the same data will give different results each time it is run. See this post for more details:

https://machinelearningmastery.com/randomness-in-machine-learning/

Dear Jason,

Thank you again for the awsome blog and clear explanations

If I understood well, RMSE should be equal to sqrt(mse), but this is not the case for my data:

Epoch 130/1000

10/200 [>………………………..] – ETA: 0s – loss: 0.0989 – rmse: 0.2656

200/200 [==============================] – 0s 64us/step – loss: 0.2856 – rmse: 0.4070

Please sir, how can we calculate the coefficient of determination

The mse may be calculated at the end of each batch, the rmse may be calculated at the end of the epoch because it is a metric.

Hi Jason, thanks for the helpful blog. Quick question regarding your reply here, if the rmse metric is calculated at the end of each epoch, why is it constantly being updated during an epoch whenever you’re training?

It is calculated/estimated per batch I believe.

Thanks for your reply. If that’s the case, why is the square root of the MSE loss function not equal to the RMSE metric value from above if they are both calculated at the end of each batch?

They should be, and if not, then there is a difference in the samples used to calculate the score – e.g. batch vs epoch, or a difference in precision between the two calculations causing rounding errors.

You could try digging into the code if this matters.

Generally, I recommend a separate standalone evaluation of model performance and only use training values as a rough/directional assessment.

For the determination coefficient I use this basic code

S1, S2 = 0, 0

for i in range(len(Y)):

S1 = S1 + (Y_pred_array[i] – mean_y)**2

S2 = S2 + (Y_array[i] – mean_y)**2

R2 = S1/S2

But this gives give bad results

How can you deal with Y_pred as iterable also it is a Tensor?

Thanks

Thanks for the article. How does Keras compute a mean statistic in a per batch fashion? Does it internally (magically) aggregate the sum and count to that point in the epoch and print the measure or does it compute the measure per batch and then again re-compute the metric at the end of each epoch over the entire data?

I believe the sum is accumulated and printed at the end of each batch or end of each epoch. I don’t recall which.

Great post and just in time as usual;

The issue is that I am trying to calculate the loss based on IoU (Intersection over union) and I have no clue how to do it using my backend (TensorFlow)

My output is like this(xmin,ymin,xmax,ymax)

Thanks

Sorry, I have not implemented (or heard of) that metric.

model.compile(loss=’mse’, optimizer=’adam’, metrics=[rmse])

Epoch 496/500

0s – loss: 1.2992e-06 – rmse: 9.7909e-04

loss is mse. Should mse = rmse^2? Above value (9.7909e-04)^2 is 9.6e-8, which mismatch 1.2992e-06. Did I misunderstand something? Thanks.

The loss and metrics might not be calculated at the same time, e.g. end of batch vs end of epoch.

Thanks for reply.

history = model.fit(X, X, epochs=500, batch_size=len(X), verbose=2)

I thought the duration of batch is equal to one epoch, since batch_size=len(X). If it is correct?

Furthermore, it seems that the loss of epoch is also updated each iteration.

Epoch 496/500

0s – loss: 1.2992e-06 – rmse: 9.7909e-04

No, one epoch is comprised of 1 or more batches. Often 32 samples per batch are used as a default.

Lear more here:

https://machinelearningmastery.com/gentle-introduction-mini-batch-gradient-descent-configure-batch-size/

Thanks a lot for your time to explain and find the link.

I am sorry. I think I did not express my thoughts correctly.

In the above example, history = model.fit(X, X, epochs=500, batch_size=len(X), verbose=2)

batch_size=len(X)

batch_size: Integer or None. Number of samples per gradient update. If unspecified, batch_size will default to 32.

Since batch_size has been specified as the length of testset, may I consider one epoch comprises 1 batch and the end of a batch is the time when an epoch is end? Model ’mse’ loss is the rmse^2.

Yes, correct.

Thanks for the great article, Jason. I have 2 questions;

1) I have a pipeline which has a sequence like : Normalizer –> KerasRegressor

Can I simply use history = pipeline.fit(..) then plot metrics ?

2) I have a KFold crossvalidation like that:

kfold = StratifiedKFold(n_splits=3)

results = cross_val_score(pipeline, X, Y, cv=kfold, scoring = mape)

How I can plot that 3 CV fits’ metrics?

Thanks.

No, I don’t believe you can easily access history when using the sklearn wrappers.

HI Dr. Jason Brownlee

Thanks for good tutorial.

What is the different between these two lines

score = model.evaluate(data2_Xscaled, data2_Yscaled, verbose=verbose)

y_hat = model.predict(data2_Xscaled)

objective metric is the customized one def rmse(y_true, y_pred)

the score value should also equal to y_hat

One evaluates the model the other makes a prediction.

Hello Jason,

Thanks for your work.

I’m using MAE as metric in a multi-class classification problem with ordered classes.

Because, in my problem it is not the same to classify a record of class 5 in the class 4, than to assign it to the class 1.

My model is:

network %

layer_dense(units = 32, activation = “relu”, input_shape = c(38)) %>%

layer_dense(units = 5, activation = “softmax”)

network %>% compile(

optimizer = “rmsprop”,

loss = “categorical_crossentropy”,

metrics = c(“mae”)

)

But the model does not correctly calculate the MAE.

It is possible to use MAE for this classification problem?

Tanks

MAE is not an appropriate measure of error for classification, it is intended for regression problems.

You can learn the difference between classification and regression here:

https://machinelearningmastery.com/faq/single-faq/what-is-the-difference-between-classification-and-regression

Do you have a code written for the mean_iou metric?

What is mean_iou?

Hi Jason,

When defining a custom metrics function, the y_true and y_pred are of type Tensor. If I have my own function that takes numpy arrays as input how do I convert y_true and y_pred to numpy arrays?

You will need to work with Tensor types. That is the expectation of Keras.

Dear Jason,

How can we use precision and recall metrics for Deep Learning with Keras in Python?

Thanx in advance.

You can make predictions with our model then use the precision and recall metrics from the sklearn library.

Hello mr Jason

I have a question that have confused me for so long.

For a multiple output regression problem, what does the MSE loss function compute exactly ?

Thank you in advance.

Nice article(s) Jason.

At run time, I wanted to bucket the classes and evaluate. So tried this function but it returns

`nan`

.def my_metric(y_true, y_pred):

actual = tf.floor( y_true / 10 )

predicted = tf.floor( y_pred / 10 )

return K.categorical_crossentropy(actual, predicted)

Sorry, I cannot debug your code. Perhaps post to stackoverflow?

Sorry. Thanks a lot. Learned some good things 🙂

Hello mr Jason

For a multiple output regression problem, what does the MSE loss function compute exactly ?

Is it the sum of the MSE over all the output variables, the average or something else ?

Thank you in advance.

The average of the squared differences between model predictions and true values.

This is for just one output, what if I have multiple outputs ?

You can calculate the metric for each time step or output. I have an example here:

https://machinelearningmastery.com/multi-step-time-series-forecasting-long-short-term-memory-networks-python/

Thank you so much for your Tutorial. Nowadays I follow your twitter proposals everyday. It’s great !

I have two questions:

1) regarding sequential model in the last example;

if I remove activation definition = ‘relu’, in your last code example … I got a surprising better RMSE performance values… it is suggest to me that has something to do with Regression issues that works better if we do not put activation at all in the first hide layer. Is it casual result or any profound reason?

2) using a same architectural model, which is better a Regression approach (we leave out the activation in the output layer) or a multinomial classification (we set up the appropriate ‘softmax’ as activation in the output layer), imagine for example, we analyze same problem, e.g. we have all continuos label output or any discrete multiclass label (for getting for example rounded real number by their equivalent integer number), for a serie of real number samples …I mean is there any intrinsic advantage or behavior using Regression analysis vs Multinomial classification ?

thanks

JG

It really depends on the problem as to the choice and benefit of activation functions.

In terms of activation in the output layer – what I think you’re asking about, the heuristics are:

– regression: use ‘linear’

– binary classification: use ‘sigmoid’

– multi-class classification: use ‘softmax’.

Does that help?

If I imagine a continuos curve for a linear regression as output of prediction vs imagine for the same problem different outputs of segments to categorize a big multi-class classification, using the same main model architecture (obviously with different units and activation at output, loss and metrics at compilation, etc) …which model will perform better the regression or the multi-class (for the same problem approach) ?

My intuition tell me that multi-class it is more fine because it can focus on specific segment output (classes) of the linear regression curve (and even it has more units at the output therefore more analysis it is involved. Do not worry to much, I try in the future to experiment with some specific examples, to search for my question.

Anyway, do you like women basket? congratulations Australia won to España (-Spain it is my country -) two hours ago…

I don’t follow, sorry.

A classification model is best for classification and will perform beyond poorly for regression.

Not a sports guy, sorry 🙂

Thanks for the tutorial.

I followed all of the steps and used my own metric function successfully. I was also able to plot it.

The problem that I encountered was when I tried to load the model and the saved weights in order to use model.evaluate_generator(). I keep getting the error: “Exception has occurred: ValueError too many values to unpack (expected 2) ”

I was wondering if you know how to solve this problem.

I have not seen this. Is your version of Keras up to date? v2.2.4 or better?

How to extract and store the accuracy output from ‘loss’ and ‘metrics’ in the model.compile step in order to pass those float values to mlflow’s log_metric() function ?

history = regr.compile(optimizer, loss = ‘mean_squared_error’, metrics =[‘mae’])

My ‘history’ variable keeps coming up as ‘None type’

That is odd, I have not seen that before.

Perhaps post to the keras user group:

https://machinelearningmastery.com/get-help-with-keras/

Hi Dr. Brownlee,

By definition, rmse should be square root of mse.

But if we fit keras with batches, rmse would not be calculated correctly.

Could you give me some advices about how to use customized rmse metric with batches fitting properly?

If you add RMSE as a metric, it will be calculated at the end of each epoch, i.e. correctly.

Why is the cosine proximity value negative in this case. Should it not be positive since the dot product computed is of the same vectors it should be +1.0 right?

Perhaps because the framework expects to minimize loss.

What would be the correct interpretation of negative value in this case? In the example you have mentioned since both the vectors were same the value we received was -1.0. When i google the meaning of it certain blogs mentioned that it means that vector are similar but in opposite directions . This does not seem a correct interpretation as both vectors are same

Sorry, i don’t have material on this measure, perhaps this will help:

https://en.wikipedia.org/wiki/Cosine_similarity

This post helps me again. You are the best. 🙂

I have a question when I write the custom metrics for my project.

Assuming that g and v are two inputs of the model, and v in the next time step is output. There is a relationship between g and v. The loss function of the model is MSE of the output. But when it comes to the metrics, I want to define it as the MSE of predicted g and observed g.

When I write a custom metric to calculate the MSE, I don’t know how to make y_true represents the observed g.

Did I make it clear?

Thank you in advance.

It might be easier to write a custom function and evaluate model performance manually.

Thank you for the advice.

I use the method you introduced in another post: https://machinelearningmastery.com/implement-machine-learning-algorithm-performance-metrics-scratch-python/

It works.

Thanks a lot!

Well done!

I’m trying to build my own accuracy function that checks if the output sequence is same as the true answer . For example if the true answer is ” 0.2 0.4 0.6 0.8 ”, either ” 0.4 0.6 0.8 0.2” or ”0.8 0.6 0.4 0.2 ” will be define as correct. Do you have any thoughts or recommendations?

You would not use accuracy, you would use an error, such as MSE, MAE or RMSE.

But I would like the out come be 1’s and 0’s not in the middle. Will that be possible?

Also merry Christmas, forgot that yesterday.

You can round a floating point value to either 0/1.

I did not find any post in your blog specifically focus on loss function, so I submit my question under this post.

There are two output features in my model. I’m not sure how the loss function works. Whether the loss function returns the sum of two calculated errors or weighted sum or some other values?

MSE = MSEa + MSEb ?

MSE = 0.5*MSEa + 0.5*MSEb ?

If it returns the weighted sum, can I define the weight?

Thank you in advance.

You can choose how to manage how to calculate loss on multiple outputs.

Adding a constant 1 or 0.5 does not make any difference in practice, I would imagine.

Hi Dr.Brownlee,

I want to define custom monitor metrics such as AUC for Early Stopping and ModelCheckpoint and other callbacks for monitor options and metrics for model.compile,

What do i do ?

I’m looking forward to your answer.

Thanks,

Create a list of callbacks and pass it to the “callbacks” argument on the fit() function.

Thanks for the tutorials.

Precision and Recall metrics have been removed from the latest version of keras, they cited that the metric was misleading, do you have any idea how to create a custom precision and recall metrics?

Yes, you can make predictions with your model then calculate the metrics with sklearn:

https://scikit-learn.org/stable/modules/classes.html#module-sklearn.metrics

Thank you so much for your tutorials.

I want to write a costume metric function. This function is PSNR (Peak signal-to-noise ratio) which is most commonly used to measure the quality of reconstruction of lossy compression codecs. My loss function is MSE.

PSNR is calculated based on the MSE results. So I was wondering if there is a way to write this PSNR function using the loss that is calculated in the fitting process. Or I should calculate MSE in the body of the function and use that information to calculate PSNR.

Also, In your code:

def rmse(y_true, y_pred):

return backend.sqrt(backend.mean(backend.square(y_pred – y_true), axis=-1))

What are the inputs of rmse during the training? How it is assigning y_true and y_pred?

The inputs to the function are the true y values and the predicted y values.

Thank you so much for your response, Jason.

This custom metric should return a tensor, right?

I had to use log10 in my computations. But then Keras only has log of e. (tf.keras.backend.log(x))

So I used math.log10 and I was getting an error in model.compile(). Here is the previous code:

def PSNR(y_true, y_pred):

max_I = 1.0

return 20*math.log10(max_I) – 10*math.log10( backend.mean( backend.square(y_pred – y_true),axis=-1)

Then, I thought I can use numpy to calculate the last line and then make a tensor of the result.

So I changed my code to:

def PSNR(y_true, y_pred):

max_I = 1.0

val = 20*math.log10(max_I) – 10*math.log10(np.mean( np.square(y_pred – y_true),axis=-1))

newTensor = K.variable(value = val)

return newTensor

I’m not getting any error. But is this the right way to do this?

Yes, you must operate upon tensors.

Sorry, I don’t have the capacity to review/debug your approach.

Thank you, Jason.

How do I resolve this error message? Please help!

In order to access val_acc you must fit the model with a validation dataset. e.g. set validation_data=(…) in the call to model.fit(…)

can a target value for mse can be given?

can the system be tested for convergence

This is a common question that I answer here:

https://machinelearningmastery.com/faq/single-faq/how-to-know-if-a-model-has-good-performance

Hi Jason,

Is there ever a limit to number of epochs? In my data set (regression) the more epochs the better the model keeps performing… Even past 500… Is anything over 2000 epochs odd??

Not really.

In regression… Ideally when should one stop adding epochs? Is it possible to verify just thru an RSME plot?

When the model no longer improves on the holdout validation dataset.

Hi Jason,

in the codes of Custom Metrics in Keras part, you defined the rmse function as follow:

def rmse(y_true, y_pred):

return backend.sqrt(backend.mean(backend.square(y_pred – y_true), axis=-1))

Why is it necessary to write axis=-1? I don’t understand what axis=-1 means here.

I deleted axis=-1 from the function in my codes but it is still OK to run?

It is explicitly specifying to calculate the error across the last dimension, normally this is samples, but for encoder-decoder lstms this will be time steps.

Hello Mr. Brownlee,

-> Thanks for this tutorial, you helped me a lot.

For my thesis, I did a regression cnn in keras using the four metrics you present here to be interesting for regression.

I’ve this question with respect to the cosine_proximity-metric: if the vectors in nominator and denominator of the underlying formula are 1-dimensional vectors (=being just the real valued true and predicted label), then the metric will always resolve to 1?

– Why is its use then so interesting for regression networks, or maybe networks with multiple regressed output are intended here?

– Have you got any idea how its value could be ‘-1’ instead of ‘+1’ when both the true and predicted label are positive?

Kind Regards from Belgium

Sorry, I can’t give you good off the cuff about the cosine similarity metric.

I hope to cover it in the future.

Hi!

I am trying to train a recurrent neural network implemented using Keras and mean square error as loss function. Is it possible to have a loss greater than 1 and the model generated by the network to work as expected?

Perhaps.

When i try to use a model saved using rmse as metric.

During loading the model

load_model(….),,,

it gives the following error

ValueError: Unknown metric function:rmse

What is the best metric for timeseries data?

My model with MSE is either good in capturing higher signals or either fails to capture low signals..

I want a better metric which would preserve correlation and MSE together..

thank you

Good question, you must provide a dict to the load_model() function that indicates what the rmse function means.

For example, and assuming the rmse function is defined:

Thanks for the reply but i still have an error.

IndexError: tuple index out of range

C:\ProgramData\Anaconda3\lib\site-packages\numpy\core\_methods.py in _count_reduce_items(arr, axis)

53 items = 1

54 for ax in axis:

—> 55 items *= arr.shape[ax]

56 return items

57

IndexError: tuple index out of range

Sorry to hear that. I don’t have any good ideas.

Perhaps try searching/posting stackoverflow?

What is the best metric for timeseries data?

My model with MSE is either good in capturing higher signals or either fails to capture low signals..

I want a better metric which would preserve correlation and MSE together..

I find RMSE or MAPE useful.

Very informative blog. But can you please tell me how to use recall as a metric.

Just plug it in to the above examples.

Hello Sir.

Please if I’ve normalized my dataset ( X and Y), with MinMaxScaler for example, and if I’m using MSE or RMSE for loss and/or for metrics, the results expected (mse and rmse) are also normalized, right?

How can I get the “real” MSE and RMSE of the original data (X and Y) denormalized?

Thanks much in advance.

Correct.

You can get real error by inverting the transform on the predictions first, then calculating error metrics. The objects typically offer an inverse_transform() function.

Ok. Right. I did it. Thanks! One more question please…

But how about if I, let’s say, normalize X and standardize Y, or vice-versa.

When inverting the transformation on the predictions [predict(X_test) = Y_pred], which scaler should I use to get the “real” Y_pred inversely transformed?

The inverse of normalized or the inverse of standardized?

You know what I mean?

Thanks much in advance.

You invert the transforms applied to y, in the reverse order in which they were applied.

This may give you some ideas:

https://machinelearningmastery.com/machine-learning-data-transforms-for-time-series-forecasting/

I tried using a custom loss function but always fall into errors.

Mahalanobis distance (or “generalized squared interpoint distance” for its squared value[3]) can also be defined as a dissimilarity measure between two random vectors x and y of the same distribution with the covariance matrix S.

d(x,y) = square [Transpose(x-y) * Inverse(S)* (x-y)]

(https://en.wikipedia.org/wiki/Mahalanobis_distance)

n_classes = 4

n_samples=800

X, y = make_classification(n_samples=n_samples, n_features=20, n_informative=4, n_redundant=0, n_classes=n_classes, n_clusters_per_class=2)

y = to_categorical(y)

Xtrainb, testXb, ytrainb, ytestb = train_test_split(X, y, test_size = 0.3, random_state=42)

x_trainb = np.reshape(Xtrainb, (Xtrainb.shape[0], Xtrainb.shape[1], 1))

Xtestb = np.reshape(testXb, (testXb.shape[0], testXb.shape[1], 1))

densesize = 4

input_datab = Input(shape=(Xtrainb.shape[1],1))

epochs = 10

batch_size = 32

########

def mahalanobis(y_true, y_pred):

x_minus_mn_with_transpose = K.transpose(y_true – y_pred)

Covariance = covr1(y_true, y_pred)

inv_covmat = tf.linalg.inv(Covariance)

x_minus_mn = y_true – y_pred

left_term = K.dot(x_minus_mn, inv_covmat)

D_square = K.dot(left_term, x_minus_mn_with_transpose)

return D_square

def covr1(y_true, y_pred):

#x_mean = K.mean(y_true)

#y_mean = K.mean(y_pred)

Cov_numerator = K.sum(((y_true – y_pred)*(y_true – y_pred)))

Cov_denomerator = len(Xtrainb)-1

Covariance = (Cov_numerator / Cov_denomerator)

return Covariance

conv1= Conv1D(filters=80, kernel_size=2, padding=’same’, input_dim=Xtrainb.shape[1])(input_datab)

maxpool = MaxPooling1D(pool_size=3, stride=3 )(conv1)

conv2= Conv1D(filters=50, kernel_size=2, padding=’same’, input_dim=Xtrainb.shape[1])(maxpool)

maxpool = MaxPooling1D(pool_size=3, stride=3)(conv2)

flatten = Flatten()(maxpool)

dense = Dense(84, activation=’relu’)(flatten)

dense = Dense(1024, activation=’relu’)(flatten)

dense = Dense(densesize, activation=’softmax’)(dense)

model = Model(inputs=[input_datab],outputs=[dense])

model.compile(loss= mahalanobis, optimizer=’adam’, metrics=[‘acc’])

hist = model.fit(x_trainb, ytrainb, validation_data=(Xtestb, ytestb), epochs=epochs, batch_size=batch_size)

Sorry to hear that, I have some suggestions here that might help:

https://machinelearningmastery.com/faq/single-faq/can-you-read-review-or-debug-my-code

Hello Sir,

I was developing MLPRegressor model like…

#create a model

nn=MLPRegressor(hidden_layer_sizes=(2, 1,),activation=’logistic’,max_iter=2000,solver=’adam’,learning_rate_init=0.1,momentum=0.7,early_stopping=True,

validation_fraction=0.15,)

history = nn.fit(X_train, y_train, )

how can I plot mape, r^2 and how can I predict for new samples. I was scaled my data using minmax scaler???

Make a prediction on the dataset then plot the real y values vs the predicted y values.

If you are using scikit-learn, not keras, then this will help you make a prediction:

https://machinelearningmastery.com/make-predictions-scikit-learn/

Dear Prof. Brownlee:

I try the following code:

from math import sqrt

Y = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) + 0.001

Y_hat = model.predict(X)

print(Y)

print(Y_hat)

score = model.evaluate(Y, Y_hat)

print(model.metrics_names)

print(“RMSE from score”, score[1])

print(“RMSE by hand”, sqrt(mean_squared_error(Y, Y_hat)))

and got

[0.101 0.201 0.301 0.401 0.501 0.601 0.701 0.801 0.901 1.001]

[[0.20046636]

[0.28566912]

[0.37087193]

[0.4557818 ]

[0.5314531 ]

[0.60712445]

[0.6827957 ]

[0.758467 ]

[0.8341383 ]

[0.90980965]]

10/10 [==============================] – 0s 98us/step

[‘loss’, ‘rmse’]

RMSE from score 0.0007852882263250649

RMSE by hand 0.06390388739172052

I do not understand why the value in the last two lines are different. Shouldn’t they be the same?

sorry, my previous post is wrong. It should be

Y = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) + 0.001

Y_hat = model.predict(Y).reshape(-1)

print(Y)

print(Y_hat)

score = model.evaluate(Y, Y)

print(model.metrics_names, score)

print(“RMSE by hand”, sqrt(mean_squared_error(Y, Y_hat)))

but the issue is the same, I cannot tell why the reported rmse is different than the last line

Should be the same. I don’t know the cause, sorry.

I think the rmse is defined incorrectly. I believe it should be, without the “, -1”

def rmse(y_true, y_pred):

return backend.sqrt( backend.mean(backend.square(y_pred – y_true)))

but not

def rmse(y_true, y_pred):

return backend.sqrt(backend.mean(backend.square(y_pred – y_true), axis=-1))

You can try with the following code to debug

import numpy as np

Y = array([0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0]) + 0.001

Y_hat = model.predict(Y).reshape(-1)

print(Y)

print(Y_hat)

score = model.evaluate(Y, Y)

print(model.metrics_names, score)

print(“RMSE by formular”, sqrt(mean_squared_error(Y, Y_hat)))

print(“Error are”, Y-Y_hat)

print(“Squared Error are”, (Y-Y_hat) ** 2)

print(“Mean Squared Error are”, np.mean((Y-Y_hat) ** 2))

print(“Root Mean Squared Error is”, sqrt(np.mean((Y-Y_hat) ** 2)))

with the one I corrected, I got

[0.101 0.201 0.301 0.401 0.501 0.601 0.701 0.801 0.901 1.001]

[0.38347098 0.38347098 0.38347098 0.38347098 0.38347098 0.38347098

0.38347098 0.38347098 0.38347098 0.38347098]

10/10 [==============================] – 0s 6ms/step

[‘loss’, ‘rmse’] [0.11056597530841827, 0.33251461386680603]

RMSE by formular 0.33251461887730416

Error are [-0.28247098 -0.18247098 -0.08247098 0.01752902 0.11752902 0.21752902

0.31752902 0.41752902 0.51752902 0.61752902]

Squared Error are [7.97898558e-02 3.32956594e-02 6.80146292e-03 3.07266461e-04

1.38130700e-02 4.73188735e-02 1.00824677e-01 1.74330481e-01

2.67836284e-01 3.81342088e-01]

Mean Squared Error are 0.11056597176711884

Root Mean Squared Error is 0.33251461887730416

But If I use your version with the “, -1” there, I got

[0.101 0.201 0.301 0.401 0.501 0.601 0.701 0.801 0.901 1.001]

[0.35035747 0.39923668 0.44811586 0.49699506 0.54587424 0.59475344

0.64363265 0.69251186 0.741391 0.7902702 ]

10/10 [==============================] – 0s 6ms/step

[‘loss’, ‘rmse’] [0.02193305641412735, 0.1278020143508911]

RMSE by formular 0.14809812299213124

Error are [-0.24935747 -0.19823668 -0.14711586 -0.09599506 -0.04487424 0.00624656

0.05736735 0.10848814 0.159609 0.21072979]

Squared Error are [6.21791493e-02 3.92977809e-02 2.16430749e-02 9.21505186e-03

2.01369724e-03 3.90194594e-05 3.29101280e-03 1.17696773e-02

2.54750319e-02 4.44070447e-02]

Mean Squared Error are 0.021933054033792435

Root Mean Squared Error is 0.14809812299213124

Notice the evaluate return 0.1278020143508911 instead of the correct 0.14809812299213124

Thanks, I will investigate.

How can I get different components of the loss function if I am using model.train_on_batch instead of model.fit? I have seen that model.train_on_batch returns me a scalar which is just the sum of different components of loss functions?

Thank you.

I’m not sure off hand, perhaps one of these resources will help:

https://machinelearningmastery.com/get-help-with-keras/

# VAE model = encoder(+sampling) + decoder

# build encoder model

def encoder_model(inputs):

x1 = Dense(intermediate_dim_1, activation=’relu’)(inputs)

x2 = Dense(intermediate_dim_2, activation=’relu’)(x1)

x3 = Dense(intermediate_dim_3, activation=’relu’)(x2)

x4 = Dense(intermediate_dim_4, activation=’relu’)(x3)

z_mean_encoded = Dense(latent_dim, name=’z_mean’)(x4)

z_log_var_encoded = Dense(latent_dim, name=’z_log_var’)(x4)

# instantiate encoder model

encoder = Model(inputs, [z_mean_encoded, z_log_var_encoded], name=’encoder’)

return encoder, z_mean_encoded, z_log_var_encoded

# build decoder model

def decoder_model():

latent_inputs = Input(shape=(latent_dim,), name=’z_sampling’)

x4 = Dense(intermediate_dim_4, activation=’relu’)(latent_inputs)

x3 = Dense(intermediate_dim_3, activation=’relu’)(x4)

x2 = Dense(intermediate_dim_2, activation=’relu’)(x3)

x1 = Dense(intermediate_dim_1, activation=’relu’)(x2)

outputs = Dense(original_dim)(x1)

# instantiate decoder model

decoder = Model(latent_inputs, outputs, name=’decoder’)

return decoder

def recon_loss(inputs,outputs):

reconstruction_loss = mse(inputs, outputs)

return K.mean(reconstruction_loss)

def latent_loss():

kl_loss = 1 + z_log_var_encoded – K.square(z_mean_encoded) – K.exp(z_log_var_encoded)

kl_loss = K.sum(kl_loss, axis=-1)

kl_loss *= -0.5

return K.mean(kl_loss)

# # reconstruction_loss *=

# kl_loss = 1 + z_log_var_encoded – K.square(z_mean_encoded) – K.exp(z_log_var_encoded)

# kl_loss = K.sum(kl_loss, axis=-1)

# kl_loss *= -0.5

# kl_loss_metric = kl_loss

# kl_loss *= beta

# vae_loss = K.mean(reconstruction_loss + kl_loss)

def total_loss(inputs,outputs, z_mean_encoded,z_log_var_encoded,beta):

reconstruction_loss = mse(inputs, outputs)

kl_loss = 1 + z_log_var_encoded – K.square(z_mean_encoded) – K.exp(z_log_var_encoded)

kl_loss = K.sum(kl_loss, axis=-1)

kl_loss *= -0.5

kl_loss *= beta

return K.mean(reconstruction_loss + kl_loss)

def sampling(args):

“””Reparameterization trick by sampling fr an isotropic unit Gaussian.

# Arguments:

args (tensor): mean and log of variance of Q(z|X)

# Returns:

z (tensor): sampled latent vector

“””

z_mean, z_log_var = args

batch = K.shape(z_mean)[0]

dim = K.int_shape(z_mean)[1] # Returns the shape of tensor or variable as a tuple of int or None entries.

# by default, random_normal has mean=0 and std=1.0

epsilon = K.random_normal(shape=(batch, dim))

return z_mean + K.exp(0.5 * z_log_var) * epsilon

if __name__ == ‘__main__’:

x_trn,x_val,y_trn,y_val = train_test_split(Cp_inputs, X_all, test_size=0.2,shuffle=True,random_state=0)

original_dim = x_trn.shape[1]

x_trn = np.reshape(x_trn, [-1, original_dim])

x_val = np.reshape(x_val, [-1, original_dim])

input_shape = (original_dim, )

inputs = Input(shape=input_shape, name=’encoder_input’)

# Define Intermediate Layer Dimension and Latent layer Dimension

intermediate_dim_1 = 128

intermediate_dim_2 = 256

intermediate_dim_3 = 128

intermediate_dim_4 = 64

latent_dim = 3

# Define batch_size / epochs / beta

epochs = 10

batch_size = 128

beta = 0.05

encoder, z_mean_encoded, z_log_var_encoded = encoder_model(inputs)

# use reparameterization trick to push the sampling out as input

z_sampled = Lambda(sampling, output_shape=(latent_dim,), name=’z’)([z_mean_encoded, z_log_var_encoded]) # Reparameterization Trick

decoder = decoder_model()

# instantiate VAE model

outputs = decoder(z_sampled) # z_sampled = sampled z from [z_mean_encoded and z_log_var_encoded]

vae = Model(inputs, outputs, name=’vae_mlp’)

total_loss = total_loss(inputs, outputs, z_mean_encoded, z_log_var_encoded, beta)

vae.compile(optimizer=’adam’, metrics=[recon_loss, latent_loss])

history = vae.fit(x_trn, epochs=epochs, batch_size=batch_size, validation_data=(x_val, None),verbose = 2)

————————————————————————————————————–

Result :

Epoch 1/10

– 1s – loss: 34.2770 – val_loss: 4.7581

Epoch 2/10

– 0s – loss: 4.1537 – val_loss: 3.4654

Epoch 3/10

– 0s – loss: 3.2343 – val_loss: 2.7032

Epoch 4/10

– 0s – loss: 2.5479 – val_loss: 2.5234

Epoch 5/10

– 0s – loss: 2.3551 – val_loss: 2.2926

Epoch 6/10

– 0s – loss: 2.2032 – val_loss: 2.1937

Epoch 7/10

– 0s – loss: 1.9983 – val_loss: 2.0159

Epoch 8/10

– 0s – loss: 1.8385 – val_loss: 1.6428

Epoch 9/10

– 0s – loss: 1.6508 – val_loss: 1.5881

Epoch 10/10

– 0s – loss: 1.5189 – val_loss: 1.4624

——————————————————————-

I am trying to make VAE model, but it does not give any metric values, which were defined as [recon_loss, latent_loss]

Can you solve this issue?

This is a common question that I answer here:

https://machinelearningmastery.com/faq/single-faq/can-you-read-review-or-debug-my-code

Hi Jason, can I find the accuracy of keras regression problem? From your notes, for keras regression problem only mse,rmse,mae. Is it possible for me to find the accuracy of this method?

No, see this:

https://machinelearningmastery.com/faq/single-faq/how-do-i-calculate-accuracy-for-regression

Thanks Jason 🙂

You’re welcome!

Hi Jason, I want to ask you how to know whether the model provide a good performance for regression? Because previously u said that we cannot know the accuracy of regression. Is it by their loss mse,mae and rmse to decide the model has the good performance? I mean if the loss of mse is below than 1, then the model are good?

Good question, see this:

https://machinelearningmastery.com/faq/single-faq/how-to-know-if-a-model-has-good-performance

i have a question in keras , i am training the keras and compiling

like model .compile(loss=’binary_crossentropy’,optimizer=’Nadam’, metrics=[precision_m])

precision as metric in comiliation stage.

after all these we do model.evaluate it will give two values like loss and accuracy

if i given precision as metrics it will train based on precision right ,aftering training ,model.evaluate will return the loss and precision value ,

am i right or not ?

please clarify the doubt on it .

Correct.

is it good give regression loss function to classification model .compilation like

model.compile(loss=mse,mae ,optimizer=adam.metrics=recall)

please suggest on this , i have given mae as loss function for classificaiton keras model ,it gives, 0.455 as recall

is that ok model ?

No. It will optimize towards the wrong goal/objective.

hi sir ,

i have question on keras compilation .

model.compile(loss=””,optmizer=””,metrics=[mae,mse,rmse])

here i have provides 3 metrics at compilation stage.

so based on which metrics it will optimize keras model, bz we are providing the 3 metrics at a time , keras model .

Metrics are not used to optimize the model, they are only used to measure model performance.

Loss is optimized.

Hi Jason,

I have used the below snippet to compile the model.

model.compile(optimizer=’adam’, loss=’binary_crossentropy’, metrics=[tf.keras.metrics.Precision()])

My question is, how can I use the history object of the model to have a line plot of the model precision at the end of each epoch? What should I use inside the bracket below?

plt.plot(model.history[‘???’])

Thanks in advance

Here is an example:

https://machinelearningmastery.com/display-deep-learning-model-training-history-in-keras/

Thanks for your help!

You’re welcome.

Hi Jason,

Is it ok if I use MSE for loss function and RMSE for metric? I have heard that we should not use the same or nearly identical functions for the same model. Is this opinion right? If I must use metrics=RMSE, which loss function I should use (if MSE is not allow)? Thank you so much!

Yes.