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Making out-of-sample forecasts can be confusing when getting started with time series data.

The statsmodels Python API provides functions for performing one-step and multi-step out-of-sample forecasts.

In this tutorial, you will clear up any confusion you have about making out-of-sample forecasts with time series data in Python.

After completing this tutorial, you will know:

- How to make a one-step out-of-sample forecast.
- How to make a multi-step out-of-sample forecast.
- The difference between the
*forecast()*and*predict()*functions.

Discover how to prepare and visualize time series data and develop autoregressive forecasting models in my new book, with 28 step-by-step tutorials, and full python code.

Let’s get started.

**Updated Apr/2019**: Updated the link to dataset.**Updated Aug/2019**: Updated data loading to use new API.

## Tutorial Overview

This tutorial is broken down into the following 5 steps:

- Dataset Description
- Split Dataset
- Develop Model
- One-Step Out-of-Sample Forecast
- Multi-Step Out-of-Sample Forecast

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## 1. Minimum Daily Temperatures Dataset

This dataset describes the minimum daily temperatures over 10 years (1981-1990) in the city of Melbourne, Australia.

The units are in degrees Celsius and there are 3,650 observations. The source of the data is credited as the Australian Bureau of Meteorology.

Download the Minimum Daily Temperatures dataset to your current working directory with the filename “*daily-minimum-temperatures.csv”*.

The example below loads the dataset as a Pandas Series.

1 2 3 4 5 6 7 8 9 10 |
# line plot of time series from pandas import read_csv from matplotlib import pyplot # load dataset series = read_csv('daily-minimum-temperatures.csv', header=0, index_col=0) # display first few rows print(series.head(20)) # line plot of dataset series.plot() pyplot.show() |

Running the example prints the first 20 rows of the loaded dataset.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 |
Date 1981-01-01 20.7 1981-01-02 17.9 1981-01-03 18.8 1981-01-04 14.6 1981-01-05 15.8 1981-01-06 15.8 1981-01-07 15.8 1981-01-08 17.4 1981-01-09 21.8 1981-01-10 20.0 1981-01-11 16.2 1981-01-12 13.3 1981-01-13 16.7 1981-01-14 21.5 1981-01-15 25.0 1981-01-16 20.7 1981-01-17 20.6 1981-01-18 24.8 1981-01-19 17.7 1981-01-20 15.5 |

A line plot of the time series is also created.

## 2. Split Dataset

We can split the dataset into two parts.

The first part is the training dataset that we will use to prepare an ARIMA model. The second part is the test dataset that we will pretend is not available. It is these time steps that we will treat as out of sample.

The dataset contains data from January 1st 1981 to December 31st 1990.

We will hold back the last 7 days of the dataset from December 1990 as the test dataset and treat those time steps as out of sample.

Specifically 1990-12-25 to 1990-12-31:

1 2 3 4 5 6 7 |
1990-12-25,12.9 1990-12-26,14.6 1990-12-27,14.0 1990-12-28,13.6 1990-12-29,13.5 1990-12-30,15.7 1990-12-31,13.0 |

The code below will load the dataset, split it into the training and validation datasets, and save them to files *dataset.csv* and *validation.csv* respectively.

1 2 3 4 5 6 7 8 |
# split the dataset from pandas import read_csv series = read_csv('daily-minimum-temperatures.csv', header=0, index_col=0) split_point = len(series) - 7 dataset, validation = series[0:split_point], series[split_point:] print('Dataset %d, Validation %d' % (len(dataset), len(validation))) dataset.to_csv('dataset.csv', index=False) validation.to_csv('validation.csv', index=False) |

Run the example and you should now have two files to work with.

The last observation in the dataset.csv is Christmas Eve 1990:

1 |
1990-12-24,10.0 |

That means Christmas Day 1990 and onwards are out-of-sample time steps for a model trained on *dataset.csv*.

## 3. Develop Model

In this section, we are going to make the data stationary and develop a simple ARIMA model.

The data has a strong seasonal component. We can neutralize this and make the data stationary by taking the seasonal difference. That is, we can take the observation for a day and subtract the observation from the same day one year ago.

This will result in a stationary dataset from which we can fit a model.

1 2 3 4 5 6 7 |
# create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) |

We can invert this operation by adding the value of the observation one year ago. We will need to do this to any forecasts made by a model trained on the seasonally adjusted data.

1 2 3 |
# invert differenced value def inverse_difference(history, yhat, interval=1): return yhat + history[-interval] |

We can fit an ARIMA model.

Fitting a strong ARIMA model to the data is not the focus of this post, so rather than going through the analysis of the problem or grid searching parameters, I will choose a simple ARIMA(7,0,7) configuration.

We can put all of this together as follows:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 |
from pandas import read_csv from statsmodels.tsa.arima_model import ARIMA import numpy # create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) # load dataset series = read_csv('dataset.csv', header=None) # seasonal difference X = series.values days_in_year = 365 differenced = difference(X, days_in_year) # fit model model = ARIMA(differenced, order=(7,0,1)) model_fit = model.fit(disp=0) # print summary of fit model print(model_fit.summary()) |

Running the example loads the dataset, takes the seasonal difference, then fits an ARIMA(7,0,7) model and prints the summary of the fit model.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 |
ARMA Model Results ============================================================================== Dep. Variable: y No. Observations: 3278 Model: ARMA(7, 1) Log Likelihood -8673.748 Method: css-mle S.D. of innovations 3.411 Date: Mon, 20 Feb 2017 AIC 17367.497 Time: 10:28:38 BIC 17428.447 Sample: 0 HQIC 17389.322 ============================================================================== coef std err z P>|z| [0.025 0.975] ------------------------------------------------------------------------------ const 0.0132 0.132 0.100 0.921 -0.246 0.273 ar.L1.y 1.1424 0.287 3.976 0.000 0.579 1.706 ar.L2.y -0.4346 0.154 -2.829 0.005 -0.736 -0.133 ar.L3.y 0.0961 0.042 2.289 0.022 0.014 0.178 ar.L4.y 0.0125 0.029 0.434 0.664 -0.044 0.069 ar.L5.y -0.0101 0.029 -0.343 0.732 -0.068 0.047 ar.L6.y 0.0119 0.027 0.448 0.654 -0.040 0.064 ar.L7.y 0.0089 0.024 0.368 0.713 -0.038 0.056 ma.L1.y -0.6157 0.287 -2.146 0.032 -1.178 -0.053 Roots ============================================================================= Real Imaginary Modulus Frequency ----------------------------------------------------------------------------- AR.1 1.2234 -0.0000j 1.2234 -0.0000 AR.2 1.2561 -1.0676j 1.6485 -0.1121 AR.3 1.2561 +1.0676j 1.6485 0.1121 AR.4 0.0349 -2.0160j 2.0163 -0.2472 AR.5 0.0349 +2.0160j 2.0163 0.2472 AR.6 -2.5770 -1.3110j 2.8913 -0.4251 AR.7 -2.5770 +1.3110j 2.8913 0.4251 MA.1 1.6242 +0.0000j 1.6242 0.0000 ----------------------------------------------------------------------------- |

We are now ready to explore making out-of-sample forecasts with the model.

## 4. One-Step Out-of-Sample Forecast

ARIMA models are great for one-step forecasts.

A one-step forecast is a forecast of the very next time step in the sequence from the available data used to fit the model.

In this case, we are interested in a one-step forecast of Christmas Day 1990:

1 |
1990-12-25 |

### Forecast Function

The statsmodel ARIMAResults object provides a *forecast()* function for making predictions.

By default, this function makes a single step out-of-sample forecast. As such, we can call it directly and make our forecast. The result of the *forecast()* function is an array containing the forecast value, the standard error of the forecast, and the confidence interval information. Now, we are only interested in the first element of this forecast, as follows.

1 2 |
# one-step out-of sample forecast forecast = model_fit.forecast()[0] |

Once made, we can invert the seasonal difference and convert the value back into the original scale.

1 2 |
# invert the differenced forecast to something usable forecast = inverse_difference(X, forecast, days_in_year) |

The complete example is listed below:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 |
from pandas import read_csv from statsmodels.tsa.arima_model import ARIMA import numpy # create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) # invert differenced value def inverse_difference(history, yhat, interval=1): return yhat + history[-interval] # load dataset series = read_csv('dataset.csv', header=None) # seasonal difference X = series.values days_in_year = 365 differenced = difference(X, days_in_year) # fit model model = ARIMA(differenced, order=(7,0,1)) model_fit = model.fit(disp=0) # one-step out-of sample forecast forecast = model_fit.forecast()[0] # invert the differenced forecast to something usable forecast = inverse_difference(X, forecast, days_in_year) print('Forecast: %f' % forecast) |

Running the example prints 14.8 degrees, which is close to the expected 12.9 degrees in the *validation.csv* file.

1 |
Forecast: 14.861669 |

### Predict Function

The statsmodel ARIMAResults object also provides a *predict()* function for making forecasts.

The predict function can be used to predict arbitrary in-sample and out-of-sample time steps, including the next out-of-sample forecast time step.

The predict function requires a start and an end to be specified, these can be the indexes of the time steps relative to the beginning of the training data used to fit the model, for example:

1 2 3 4 |
# one-step out of sample forecast start_index = len(differenced) end_index = len(differenced) forecast = model_fit.predict(start=start_index, end=end_index) |

The start and end can also be a datetime string or a “datetime” type; for example:

1 2 3 |
start_index = '1990-12-25' end_index = '1990-12-25' forecast = model_fit.predict(start=start_index, end=end_index) |

and

1 2 3 4 |
from pandas import datetime start_index = datetime(1990, 12, 25) end_index = datetime(1990, 12, 26) forecast = model_fit.predict(start=start_index, end=end_index) |

Using anything other than the time step indexes results in an error on my system, as follows:

1 |
AttributeError: 'NoneType' object has no attribute 'get_loc' |

Perhaps you will have more luck; for now, I am sticking with the time step indexes.

The complete example is listed below:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 |
from pandas import read_csv from statsmodels.tsa.arima_model import ARIMA import numpy from pandas import datetime # create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) # invert differenced value def inverse_difference(history, yhat, interval=1): return yhat + history[-interval] # load dataset series = read_csv('dataset.csv', header=None) # seasonal difference X = series.values days_in_year = 365 differenced = difference(X, days_in_year) # fit model model = ARIMA(differenced, order=(7,0,1)) model_fit = model.fit(disp=0) # one-step out of sample forecast start_index = len(differenced) end_index = len(differenced) forecast = model_fit.predict(start=start_index, end=end_index) # invert the differenced forecast to something usable forecast = inverse_difference(X, forecast, days_in_year) print('Forecast: %f' % forecast) |

Running the example prints the same forecast as above when using the *forecast()* function.

1 |
Forecast: 14.861669 |

You can see that the predict function is more flexible. You can specify any point or contiguous forecast interval in or out of sample.

Now that we know how to make a one-step forecast, we can now make some multi-step forecasts.

## 5. Multi-Step Out-of-Sample Forecast

We can also make multi-step forecasts using the *forecast()* and *predict()* functions.

It is common with weather data to make one week (7-day) forecasts, so in this section we will look at predicting the minimum daily temperature for the next 7 out-of-sample time steps.

### Forecast Function

The *forecast()* function has an argument called *steps* that allows you to specify the number of time steps to forecast.

By default, this argument is set to 1 for a one-step out-of-sample forecast. We can set it to 7 to get a forecast for the next 7 days.

1 2 |
# multi-step out-of-sample forecast forecast = model_fit.forecast(steps=7)[0] |

We can then invert each forecasted time step, one at a time and print the values. Note that to invert the forecast value for t+2, we need the inverted forecast value for t+1. Here, we add them to the end of a list called history for use when calling *inverse_difference()*.

1 2 3 4 5 6 7 8 |
# invert the differenced forecast to something usable history = [x for x in X] day = 1 for yhat in forecast: inverted = inverse_difference(history, yhat, days_in_year) print('Day %d: %f' % (day, inverted)) history.append(inverted) day += 1 |

The complete example is listed below:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 |
from pandas import read_csv from statsmodels.tsa.arima_model import ARIMA import numpy # create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) # invert differenced value def inverse_difference(history, yhat, interval=1): return yhat + history[-interval] # load dataset series = read_csv('dataset.csv', header=None) # seasonal difference X = series.values days_in_year = 365 differenced = difference(X, days_in_year) # fit model model = ARIMA(differenced, order=(7,0,1)) model_fit = model.fit(disp=0) # multi-step out-of-sample forecast forecast = model_fit.forecast(steps=7)[0] # invert the differenced forecast to something usable history = [x for x in X] day = 1 for yhat in forecast: inverted = inverse_difference(history, yhat, days_in_year) print('Day %d: %f' % (day, inverted)) history.append(inverted) day += 1 |

Running the example prints the forecast for the next 7 days.

1 2 3 4 5 6 7 |
Day 1: 14.861669 Day 2: 15.628784 Day 3: 13.331349 Day 4: 11.722413 Day 5: 10.421523 Day 6: 14.415549 Day 7: 12.674711 |

### Predict Function

The *predict()* function can also forecast the next 7 out-of-sample time steps.

Using time step indexes, we can specify the end index as 6 more time steps in the future; for example:

1 2 3 4 |
# multi-step out-of-sample forecast start_index = len(differenced) end_index = start_index + 6 forecast = model_fit.predict(start=start_index, end=end_index) |

The complete example is listed below.

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 |
from pandas import read_csv from statsmodels.tsa.arima_model import ARIMA import numpy # create a differenced series def difference(dataset, interval=1): diff = list() for i in range(interval, len(dataset)): value = dataset[i] - dataset[i - interval] diff.append(value) return numpy.array(diff) # invert differenced value def inverse_difference(history, yhat, interval=1): return yhat + history[-interval] # load dataset series = read_csv('dataset.csv', header=None) # seasonal difference X = series.values days_in_year = 365 differenced = difference(X, days_in_year) # fit model model = ARIMA(differenced, order=(7,0,1)) model_fit = model.fit(disp=0) # multi-step out-of-sample forecast start_index = len(differenced) end_index = start_index + 6 forecast = model_fit.predict(start=start_index, end=end_index) # invert the differenced forecast to something usable history = [x for x in X] day = 1 for yhat in forecast: inverted = inverse_difference(history, yhat, days_in_year) print('Day %d: %f' % (day, inverted)) history.append(inverted) day += 1 |

Running the example produces the same results as calling the *forecast()* function in the previous section, as you would expect.

1 2 3 4 5 6 7 |
Day 1: 14.861669 Day 2: 15.628784 Day 3: 13.331349 Day 4: 11.722413 Day 5: 10.421523 Day 6: 14.415549 Day 7: 12.674711 |

## Summary

In this tutorial, you discovered how to make out-of-sample forecasts in Python using statsmodels.

Specifically, you learned:

- How to make a one-step out-of-sample forecast.
- How to make a 7-day multi-step out-of-sample forecast.
- How to use both the
*forecast()*and*predict()*functions when forecasting.

Do you have any questions about out-of-sample forecasts, or about this post? Ask your questions in the comments and I will do my best to answer.

Your tutorials are the most helpful machine learning resources I have found on the Internet and have been hugely helpful in work and personal side projects. I don’t know if you take requests but I’d love to see a series of posts on recommender systems one of these days!

Thanks Steve, and great suggestion! Thanks.

Hi,

This is a really nice example. Do you know if the ARIMA class allows to define the specification of the model without going through the fitting procedure. Let’s say I have parameters that were estimated using a dataset that I no longer have but I still want to produce a forecast.

Thanks

I expect you can set the coefficients explicitly within the ARIMA model.

Sorry I do not have an example, this post may be relevant:

http://machinelearningmastery.com/make-manual-predictions-arima-models-python/

sir,

would it be possible to do the same using LSTM RNN ?

if it is would you please come up with a blog?

Thanking you

Yes.

Any of my LSTM tutorials show how to make out of sample forecasts. For example:

http://machinelearningmastery.com/multi-step-time-series-forecasting-long-short-term-memory-networks-python/

I tried to run the above example without any seasonal difference with given below code.

from pandas import Series

from matplotlib import pyplot

from pandas import Series

from statsmodels.tsa.arima_model import ARIMA

# load dataset

series = Series.from_csv(‘daily-minimum-temperatures.csv’, header=0)

print(series.head(20))

series.plot()

pyplot.show()

split_point = len(series) – 7

dataset, validation = series[0:split_point], series[split_point:]

print(‘Dataset %d, Validation %d’ % (len(dataset), len(validation)))

dataset.to_csv(‘dataset.csv’)

validation.to_csv(‘validation.csv’)

series = Series.from_csv(‘dataset.csv’, header=None)

model = ARIMA(series, order=(7,0,1))

model_fit = model.fit(disp=0)

forecast = model_fit.forecast(steps=7)[0]

print(‘Forecast: %f’ % forecast)

for the code i am getting an error:

TypeError: only length-1 arrays can be converted to Python scalars

how can i solve this? it does well for single step forecast

I would recommend double checking your data, make sure any footer information was deleted.

What does ‘seasonal difference’ mean?

And what are the details of:

‘Once made, we can invert the seasonal difference and convert the value back into the original scale.’

Is it worth to test this code with non-seasonal data or is there another ARIMA-tutorial for non-seasonal approaches on this site?

See this post:

http://machinelearningmastery.com/seasonal-persistence-forecasting-python/

And this post:

http://machinelearningmastery.com/time-series-seasonality-with-python/

Please use the search feature of the blog.

If I pretend data in test-partition is not given, does this tutorial do the same except of the seasonal cleaning?

http://machinelearningmastery.com/tune-arima-parameters-python/

Hi Jason really it was great article

I have one doubt say when future data coming from weather station due to some fault values are missing if we randomly miss some data from sensor then I need to fill it using ARIMA by using prediction method

But here start and end date parameter is required so can I pass only start date and end date can I left it blank is it works ?

Perhaps experiment and see what works best for your use case.

Can I obtain a train RMSE from this example. Is training involved?

The model is trained, then the trained model is used to make a forecast.

Consider reading and working through the tutorial.

I did so several times.

How can I obtain a train RMSE from the model?

See this post on how to estimate the skill of a model prior to using it to make out of sample predictions:

http://machinelearningmastery.com/backtest-machine-learning-models-time-series-forecasting/

See this post to understand the difference between evaluating a model and using a final model to make predictions:

http://machinelearningmastery.com/train-final-machine-learning-model/

I actually meant obtain a train RMSE from the model in the example.

As I understand the model was trained before making an out of sample prediction.

If we place a

print(model_fit.summary())

right after fitting/training it prints some information’s, but no train RMSE.

A)

Is there a way to use the summery-information to obtain a train RMSE?

B)

Is there a way in Python to obtain all properties and methods from the model_fit object- like in other languages?

Yes, this tutorial assumes you have already estimated the skill of your model and are now ready to use it to make forecasts.

Estimating the skill of the model is a different task. You can do this using walk forward validation or a train/test split evaluation.

Is this the line where the training happens?

model = ARIMA(differenced, order=(7,0,1))

No here:

Yes I know. I actually thought there could be a direct answer to A) and B).

I would use it for archiving.

If I write: ‘split_point = len(series) – 0’ while my last datapoint in dataset is from today.

Would I have a valid forecast for tomorrow?

thanks a lot for the nice detailed article, i followed all steps and they all seem working properly, i seek your support Dr. to help me organize my project.

i have a raw data for temperature readings for some nodes (hourly readings), i selected the training set and divided them to test and training sets.

i used ARINA model to train and test and i got Test MSE: 3.716.

now i need to expose the mass raw data to the trained model, then get the forecased values vs. the actual values in the same csv file.

what should i do

*ARIMA

I’m not sure I follow. Consider this post on how to evaluate a time series model:

http://machinelearningmastery.com/backtest-machine-learning-models-time-series-forecasting/

Thank you Jason for this wonderful post… It is very detailed and easy to understand..

Do you also have something similar for LSTM Neural Network algorithm as well? something like – How to Make Out-of-Sample Forecasts with LSTM in Python.

If not, will you write one blog like this with detail explanation? I am sure there are lot of people have the same question.

Almost every post I have on LSTMs shows how to make out of sample forecasts. The code is wrapped up in the walk-forward validation.

Hi Jason,

Thanks a lot for this lesson. It was pretty straightforward and easy to follow. It would have been a nice bonus to show how to evaluate the forecasts though with standard metrics. We separated the validation set out and forecasted values for that week, but didn’t compare to see how accurate the forecast was.

On that note, I want to ask, does it make sense to use R^2 to score a time series forecast against test data? I’m trying to create absolute benchmarks for a time series that I’m analyzing and want to report unit-independent metrics, i.e. not standard RMSE that is necessarily expressed in the problem’s unit scale. What about standardizing the data using zero mean and unit variance, fitting ARIMA, forecasting, and reporting that RMSE? I’ve been doing this and taking the R^2 and the results are pretty interpretable. RMSE: 0.149 / R^2: 0.8732, but I’m just wondering if doing things this way doesn’t invalidate something along the way. Just want to be correct in my process.

Thanks!

We do that in other posts. Tens of other posts in fact.

This post was laser focused on “how do I make a prediction when I don’t know the real answer”.

Yes, if R^2 is meaningful to you, that you can interpret it in your domain.

Generally, I recommend inverting all transforms on the prediction and then evaluating model skill at least for RMSE or MAE where you want apples-to-apples. This may be less of a concern for an R^2.

Seriously amazing. Thanks a lot professor

Thanks. Also, I’m not a professor.

I get this error from your code

Traceback (most recent call last):

File “..”, line 22, in

differenced = difference(X, days_in_year)

File “..”, line 9, in difference

value = dataset[i] – dataset[i – interval]

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

Cant tell where the problem is.

Perhaps check that you have loaded your data correct (as real values) and that you have copied all of the code from the post without extra white space.

Hi Jason,

Thanks for this detailled explanation. Very clear.

Do you know if it is possible to use the fitted parameters of an ARMA model (ARMAResults.params) and apply it on an other data set ?

I have an online process that compute a forecasting and I would like to have only one learning process (one usage of the fit() function). The rest of the time, I would like to applied the previously found parameters to the data.

Thanks in advance !

Yes, you can use a grid search:

https://machinelearningmastery.com/grid-search-arima-hyperparameters-with-python/

Have you solved the problems?

look forward to your reply.

Ciao Jason,

Thanks for this tutorial and all the time series related ones. There is always a sense of order in how you write both posts and code.

I’m by the way still confused about something which is probably more conceptual about ARIMA.

The ARIMA parameters specify the lag which it uses to forecast.

In your case you used p=7 for example so that you would take into consideration the previous week.

A first silly question is why do I need to fit an entire year of data if Im only looking at my window/lags ?

The second question is that fitting my model I get an error which is really minimal even if I use a short training (2 days vs 1 year) which would reinforce my first point.

What am I missing?

Thanks

The model needs lots of examples in order to generalize to new cases.

More data is often better, to a point of diminishing returns in terms of model skill.

Hi Jason. Thanks for this awesome post.

But I have a question that is it possible to fit a multivariable time series using ARIMA model? Let’s say we have a 312-dimension at each time step in the dataset.

Thanks!

Yes, but you will need to use an extension of ARIMA called ARIMAX. I do not have an example, sorry.

Hi Dr Brownlee, thanks so much for the tutorials!

I’ve searched but didn’t find anyhting – perhaps my fault…

But do you have any tutorials or suggestions about forecasting with limited historical observations? Specifically, I’m in a position where some sensors may have a very limited set of historical observations (complete, but short, say it’s only been online for a month), but I have many sensors which could possibly be used as historical analogies (multiple years of data).

I’ve considered constructing a process that uses each large-history sensor as the “Training” set, and iterating over each sensor and finding which sensor best predicts the observed readings for the newer sensors.

However I’m struggling to find any established best practices for this type of thing. Do you have any suggestions for me?

If not I understand, but I really appreciate all the insight you’ve given over these tutorials and in your book!

Great question.

You might be able to use the historical data or models for different but similar sensors (one some dimension). Get creative!

I would likely just be looking at the RMSE and MAE to gauge accuracy, correct? Is there another measure of fitness I would be wise to consider?

No MSE and RMSE are error scores for regression problems. Accuracy is for classification problems (predicting a label).

Hi, Geat tutorial. A question about the difference function. How is it accounting for leap years?

It doesn’t, that would be a good extension to this tutorial.

Is it possible to apply seasonal_decompose on the dataset used in this tutorial since it’s a daily forecast. Most applications of seasonal_decompose i have seen are usually on monthly and quarterly data

Yes, you could use it on this data.

Thank you for an amazing tutorial. I wanted to ask if I can store the multiple step values that are predicted in the end of your tutorial into a variable for comparison with actual/real values?

Sure, you can assign them to a variable or save them to file.

Thank you for the amazing blog!, I am finding it difficult to assign multi-step values to variable, Could you please help me with the same.

Thanks in Advance!

What is the problem exactly?

Hi Jason, Thank you for the amazing blog, could you please help me with assigning multi-step predict values to variable.

You can use the forecast() function and specify the number of steps.

Thank you for your response Jason, I am getting different values with forecast() function and with predict() function, Predict function values are more accurate so I want them to assigned to variable, Can that be done? If yes what changes can I make.

Thanks in Advance!

That is surprising, if not impossible.

Perhaps confirm that you are providing the same arguments/data/model in both cases?

No Worries, I got it – Thank you

@Jason, Thanks for this, but my dataset is in a different format, it’s in YYYY-MM-DD HH:MI:SS, and the data is hourly data, let say if we have data till 11/25/2017 23:00 5.486691952

And we need to predict the next day’s data, so we need to predict our next 24 steps, what needs to be done?

Need a help on this.

Sure, you can specify the date-time format when loading the Pandas Series.

You can predict multiple steps using the predict() function.

One more question on top of my previous question,

let say my data is hourly data, and i have one week’s data as of now, as per your code do i have to take the days_in_year parameter as 7 for my case?

And as per my data’s ACF & PACF, my model should be ARIMA(xyz, order=(4,1,2))

and taking the days_in_year parameter as 7, is giving my results, but not sure how correct is that.. please elaborate a bit @Jason

I would recommend tuning the model to your specific data.

Hi Jason,

I am bugging you, but here’s my last question, my model is ready and i have predicted the p,d,q values as per the ACF, PACF plots.

Now my code looks like this:

Here, as i am appending obs to the history data, what if i add my prediction to history and then pass it to the model, do i have to run this in a loop to predict pdq values again in a loop?

My question is, if we are doing Recursive multi step forecast do we have to run the history data to multiple ARIMA models, or can we just use history.append(yhat) in the above code and get my results?

Recursive multi-step means you will use predictions as history when you re-fit the model.

Reply to my previous response, so predictions to be added as history, that’s fine, we will be doing history.append(yhat) instead of history.append(obs), but do we have to run the above code using the same ARIMA model i.e. 6,1,2 or for each history we will determine the pdq values and run on multiple ARIMA models to get the next predictions?

I hope, you are getting my point.

It is up to you.

Hello,

I am actually working on a project for implicit volatility forecasting. My forecast is multi-output Your tutorial has been a lot of help but i just want to clarify something please.

1. Is it okay to train on the all dataset and not divide it in train/test?

2. What is the sample of data selected for the forecast function? I mean is it the 7 last values of the original dataset?

Thank you

You must evaluate the skill of your model on data not seen during training. Here’s how to do that with time series:

https://machinelearningmastery.com/backtest-machine-learning-models-time-series-forecasting/

How do we add more input parameters? Like for example, i would like to predict the weather forecast based on historic forecast but i would also like to consider, say the total number of rainy days last 10 years and have both influence my prediction?

You may have to use a different linear model such as ARIMAX.

Thank you.

Do you have any samples that I could learn from or use as a base to build my own forecast? Similar to the article that you shared above?

Perhaps try searching the blog and see if there is a tutorial that is a good fit?

Will do that. Thanks!

Hey Jason, let’s say if I wanted to forecast the value in the next 365 days, so I just simply change the line below to:

forecast = model_fit.forecast(steps=365)[0]

Will it works? Thanks!

Yes, but expect skill to be very poor.

Thanks so much Jason! But just a quick check with you, why are you splitting the dataset into two different csv: dataset.csv and validation.csv? What is the purpose each of the csv?

This post might clear things up:

https://machinelearningmastery.com/difference-test-validation-datasets/

Hi Jason,

Thank you for sharing a such wonderful article with us which I am looking for a while.

However, I got an error of “ValueError: The computed initial AR coefficients are not stationary.” when run your code block 5 beneath “We can put all of this together as follows:”

If I run it under Sypder, I got “cannot import name ‘recarray_select'”.

It would be appreciated if you could give me some clue how to fix it.

Thank you!

Chuck

Was this with the data provided in the post or your own data?

You can learn more about stationarity here:

https://machinelearningmastery.com/time-series-data-stationary-python/

how can we calculate the total RMSE?

The square root of the mean squared differences between predicted and expected values.

Hi Jason,

Thanks for the wonderful post.

One thing which I can’t understand is that we are forecasting for the next 7 days in the same dataset (dataset.csv) that we have trained the model on.

In other words, in the initial steps we had split the data into ‘dataset.csv’ and ‘validation.csv’ and then we fit the ARIMA on ‘dataset.csv’ but we never called ‘validation.csv’ before making a forecast. How does it wok?

No, we are forecasting beyond the end of dataset.csv as though validation.csv does not exist. We can then look in validation.csv and see how our forecasts compare.

Perhaps re-read the tutorial?

yep! got it. Actually I have exogenous inputs as well. So, I had to use ‘validation’ dataset as well.

Great.

Hi jason

Can you tell why did we leave the test data as it is?

and what if so in the above method we dont separate the training and testing data?

In the above tutorial we are pretending we are making an out of sample forecast, e.g. that we do not know the true outcome values.

Could you please tell about what should be changed in the code if multivariate analysis is done, i.e, if we have extra 3 features in dataset.

Different methods will need to be used. I hope to have examples soon.

Hi Jason, Thanks for the post..very intuitive. I am at Step3: Developing Model. I ran through the other doc on: how to choose your grid params for ARIMA configuration and came up with (10,0,0) with the lowest MSerror. I do the following:

# seasonal difference

X = series.values

days_in_year = 365

differenced = difference(X, days_in_year)

# fit model

model = ARIMA(differenced, order=(10,0,0))

and get error: Insufficient degrees of freedom to estimate.

My data is on monthly level (e.g. 1/31/2014, 2/28/2014, 3/31/2014)..I have 12 readings from each year of 2014-2017+3 readings from 2018 making it 52 readings. Do I have to change the #seasonal difference based on this?

Thanks

It is a good idea to seasonally adjust if you have a seasonal component or model it directly via SARIMA.

i am getting same problem what should i do to rectify it

@ Jason

Thank you for your article, this is helpful.

I used Shampo sales dataset and used ARIMA Forecast & Predict function for next 12 months but i get different results.

Perhaps you have done something different to the tutorial?

Hello sir,

Can you please tell me how i can take the predicted output to a CSV ?

Thank you!

You can save an array as a CSV File via numpy.

https://docs.scipy.org/doc/numpy-1.14.0/reference/generated/numpy.savetxt.html

Hi, @Jason

I am trying to use predict(start, end), and I found only integer parameter will work. I want to specify the start and end by a date, but it gives me an error:

‘only integers, slices (

`:`

), ellipsis (`...`

), numpy.newaxis (`None`

) and integer or boolean arrays are valid indices’I have searched a lot online, but none of them work. Thank you so much!

The API says it does support dates, and I assume your data must be a pandas Series. I have not tried it though, sorry.

If my dataset is less than 365 days it is showng an error in the below code:If my dataset is of just 50rows how that can be perfomed?

from pandas import Series

from statsmodels.tsa.arima_model import ARIMA

import numpy

# create a differenced series

def difference(dataset, interval=1):

diff = list()

for i in range(interval, len(dataset)):

value = dataset[i] – dataset[i – interval]

diff.append(value)

return numpy.array(diff)

# invert differenced value

def inverse_difference(history, yhat, interval=1):

return yhat + history[-interval]

# load dataset

series = Series.from_csv(‘dataset.csv’, header=None)

# seasonal difference

X = series.values

days_in_year = 365

differenced = difference(X, days_in_year)

# fit model

model = ARIMA(differenced, order=(7,0,1))

model_fit = model.fit(disp=0)

# multi-step out-of-sample forecast

forecast = model_fit.forecast(steps=7)[0]

# invert the differenced forecast to something usable

history = [x for x in X]

day = 1

for yhat in forecast:

inverted = inverse_difference(history, yhat, days_in_year)

print(‘Day %d: %f’ % (day, inverted))

history.append(inverted)

day += 1

Sorry, I cannot debug your example.

I am trying to apply this code to other dataset, but I get this error. Please, any help?

C:\Users\Fel\Anaconda3\lib\site-packages\statsmodels\tsa\tsatools.py:676: RuntimeWarning: divide by zero encountered in true_divide

invmacoefs = -np.log((1-macoefs)/(1+macoefs))

C:\Users\Fel\Anaconda3\lib\site-packages\statsmodels\tsa\tsatools.py:650: RuntimeWarning: invalid value encountered in true_divide

newparams = ((1-np.exp(-params))/(1+np.exp(-params))).copy()

C:\Users\Fel\Anaconda3\lib\site-packages\statsmodels\tsa\tsatools.py:651: RuntimeWarning: invalid value encountered in true_divide

tmp = ((1-np.exp(-params))/(1+np.exp(-params))).copy()

—————————————————————————

LinAlgError Traceback (most recent call last)

in ()

24 # fit model

25 model = ARIMA(differenced, order=(7,0,1))

—> 26 model_fit = model.fit(disp=0)

27 # multi-step out-of-sample forecast

28 forecast = model_fit.forecast(steps=period_forecast)[0]

~\Anaconda3\lib\site-packages\statsmodels\tsa\arima_model.py in fit(self, start_params, trend, method, transparams, solver, maxiter, full_output, disp, callback, start_ar_lags, **kwargs)

957 maxiter=maxiter,

958 full_output=full_output, disp=disp,

–> 959 callback=callback, **kwargs)

960 params = mlefit.params

961

~\Anaconda3\lib\site-packages\statsmodels\base\model.py in fit(self, start_params, method, maxiter, full_output, disp, fargs, callback, retall, skip_hessian, **kwargs)

464 callback=callback,

465 retall=retall,

–> 466 full_output=full_output)

467

468 # NOTE: this is for fit_regularized and should be generalized

~\Anaconda3\lib\site-packages\statsmodels\base\optimizer.py in _fit(self, objective, gradient, start_params, fargs, kwargs, hessian, method, maxiter, full_output, disp, callback, retall)

189 disp=disp, maxiter=maxiter, callback=callback,

190 retall=retall, full_output=full_output,

–> 191 hess=hessian)

192

193 optim_settings = {‘optimizer’: method, ‘start_params’: start_params,

~\Anaconda3\lib\site-packages\statsmodels\base\optimizer.py in _fit_lbfgs(f, score, start_params, fargs, kwargs, disp, maxiter, callback, retall, full_output, hess)

408 callback=callback, args=fargs,

409 bounds=bounds, disp=disp,

–> 410 **extra_kwargs)

411

412 if full_output:

~\Anaconda3\lib\site-packages\scipy\optimize\lbfgsb.py in fmin_l_bfgs_b(func, x0, fprime, args, approx_grad, bounds, m, factr, pgtol, epsilon, iprint, maxfun, maxiter, disp, callback, maxls)

197

198 res = _minimize_lbfgsb(fun, x0, args=args, jac=jac, bounds=bounds,

–> 199 **opts)

200 d = {‘grad’: res[‘jac’],

201 ‘task’: res[‘message’],

~\Anaconda3\lib\site-packages\scipy\optimize\lbfgsb.py in _minimize_lbfgsb(fun, x0, args, jac, bounds, disp, maxcor, ftol, gtol, eps, maxfun, maxiter, iprint, callback, maxls, **unknown_options)

333 # until the completion of the current minimization iteration.

334 # Overwrite f and g:

–> 335 f, g = func_and_grad(x)

336 elif task_str.startswith(b’NEW_X’):

337 # new iteration

~\Anaconda3\lib\site-packages\scipy\optimize\lbfgsb.py in func_and_grad(x)

278 if jac is None:

279 def func_and_grad(x):

–> 280 f = fun(x, *args)

281 g = _approx_fprime_helper(x, fun, epsilon, args=args, f0=f)

282 return f, g

~\Anaconda3\lib\site-packages\scipy\optimize\optimize.py in function_wrapper(*wrapper_args)

291 def function_wrapper(*wrapper_args):

292 ncalls[0] += 1

–> 293 return function(*(wrapper_args + args))

294

295 return ncalls, function_wrapper

~\Anaconda3\lib\site-packages\statsmodels\base\model.py in f(params, *args)

438

439 def f(params, *args):

–> 440 return -self.loglike(params, *args) / nobs

441

442 if method == ‘newton’:

~\Anaconda3\lib\site-packages\statsmodels\tsa\arima_model.py in loglike(self, params, set_sigma2)

778 method = self.method

779 if method in [‘mle’, ‘css-mle’]:

–> 780 return self.loglike_kalman(params, set_sigma2)

781 elif method == ‘css’:

782 return self.loglike_css(params, set_sigma2)

~\Anaconda3\lib\site-packages\statsmodels\tsa\arima_model.py in loglike_kalman(self, params, set_sigma2)

788 Compute exact loglikelihood for ARMA(p,q) model by the Kalman Filter.

789 “””

–> 790 return KalmanFilter.loglike(params, self, set_sigma2)

791

792 def loglike_css(self, params, set_sigma2=True):

~\Anaconda3\lib\site-packages\statsmodels\tsa\kalmanf\kalmanfilter.py in loglike(cls, params, arma_model, set_sigma2)

647 loglike, sigma2 = kalman_loglike.kalman_loglike_double(y, k,

648 k_ar, k_ma, k_lags, int(nobs), Z_mat,

–> 649 R_mat, T_mat)

650 elif issubdtype(paramsdtype, np.complex128):

651 loglike, sigma2 = kalman_loglike.kalman_loglike_complex(y, k,

kalman_loglike.pyx in statsmodels.tsa.kalmanf.kalman_loglike.kalman_loglike_double()

kalman_loglike.pyx in statsmodels.tsa.kalmanf.kalman_loglike.kalman_filter_double()

~\Anaconda3\lib\site-packages\numpy\linalg\linalg.py in pinv(a, rcond)

1722 return wrap(res)

1723 a = a.conjugate()

-> 1724 u, s, vt = svd(a, full_matrices=False)

1725

1726 # discard small singular values

~\Anaconda3\lib\site-packages\numpy\linalg\linalg.py in svd(a, full_matrices, compute_uv)

1442

1443 signature = ‘D->DdD’ if isComplexType(t) else ‘d->ddd’

-> 1444 u, s, vh = gufunc(a, signature=signature, extobj=extobj)

1445 u = u.astype(result_t, copy=False)

1446 s = s.astype(_realType(result_t), copy=False)

~\Anaconda3\lib\site-packages\numpy\linalg\linalg.py in _raise_linalgerror_svd_nonconvergence(err, flag)

96

97 def _raise_linalgerror_svd_nonconvergence(err, flag):

—> 98 raise LinAlgError(“SVD did not converge”)

99

100 def get_linalg_error_extobj(callback):

LinAlgError: SVD did not converge

Perhaps try some other configurations of the model?

Perhaps try to scale or difference your data first?

Perhaps try more or less data?

Truly an outstanding work. I had been searching all over the net for the forecast and predict functions and this made my day. Thank you for this wonderful knowledge.

Do share your YouTube channel link if you have a channel, I would love to subscribe.

Thanks.

I don’t make videos. Developers learn by doing, not watching.

I get this error from your code

Traceback (most recent call last):

File “..”, line 22, in

differenced = difference(X, days_in_year)

File “..”, line 9, in difference

value = dataset[i] – dataset[i – interval]

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

Cant tell where the problem is.

Ensure that you copy the complete example and preserve indenting.

Thanks Jason. this is very helpful.

When I run the original dataset, train it and test it, I get a MSE of .09 which is very good where I use (p,d,q) as 2,1,0.

My dataset contains 60 observations out of I push 12 to validation set.

When I forecasted using step=12 and did a MSE with validation set, I get a MSE of .42.

Is this expected and is it a good measure?

regards

Bhadri.

The idea of “good” is really problem specific, I explain more here:

https://machinelearningmastery.com/faq/single-faq/how-to-know-if-a-model-has-good-performance

Hi Jason,

Thanks ever so much for this post! Your posts are all very clear and easy to follow. I cannot steady the heavily mathematical stuff, it just confuses me.

I have a question. If my daily data is for Mondays-Fridays, should I adjust the number of days in a year to 194 instead of 365? That is the total number of days in this year excluding holidays and weekends in Germany.

Regards,

S:N

It really depends if you need to seasonally adjust the data or not.

Learn more here:

https://machinelearningmastery.com/remove-trends-seasonality-difference-transform-python/

Dear Jason, thank you very much for the tutorial. Is it normal that if I do a long-term prediction (for instance, 200 steps) the performance of the predictor degradates? In particular, I observe that the prediction converges to a certain value. What can I do to perform a long term out-of-sample prediction?

Yes, the further into the future you predict, the worse the performance. Predicting the future is very hard.

Hi Jason, Thank you very much for the post.

I checked stationarity test for the provided data-set with Augmented Dickey-Fuller method and below is the result

Test Statistic -4.445747

p-value 0.000246

#Lags Used 20.000000

Number of Observation Used 3629.000000

Critical Value (1%) -3.432153

Critical Value (5%) -2.862337

Critical Value (10%) -2.567194

The result shows that data looks stationary. So my question is

1. Even though data is stationary why did you apply Seasonality dereference ?

2. You have taken seasonality dereference of data and the parameter d of ARIMA model is still 0(ARIMA model 7 0 1). isn’t required to mention d > 0(No of dereference taken) when dereference has applied on actual data?

The problem is easier to model with the seasonality removed.

The d parameter is intended to counter any trend, there is no trend, therefore d can remain zero.

Hi, this is wonderful.

I have a small question about the out of sample one step forecast for several days. For example, I need to predict data from 1990-12-25 to 1990-12-31, and I want to use one step forecast for every. How can I make it using api predict or forecast? Thanks.

I believe the example in the tutorial above does this. Perhaps I don’t understand your question?

Well, thanks for the reply.

Let’s talk about the 7 data from 1990-12-25 to 1990-12-31 that needs to be forecasted. In your tutorial, you use the function forecast(period=7) getting the forecasting in one time. But I want to only use the function forecast(period=1) in 7 times to make the forecasting. For forecast(period=7), the new predicted data would affect the next data to be predicted(for example, the predicted data 1990-12-25 would affect the data 1990-12-26 to be predicted). For forecast(period=1), every predicted data is affected by the real data. That is to say, when predicting 1990-12-26, the real data 1990-12-25 would add into the model, not the predicted data 1990-12-25 like in forecast(period=7). My question is how to program the dynamic data update using statsmodels.

Forgive my unskilled expression.

Ahh, I see, thanks.

I assume that real observations are made available after each prediction, so that they can be used as input.

The simplest answer is to re-fit the model with the new obs and make a 1-step prediction.

The complex answer is to study the API/code and figure out how to provide the dynamic input, I’m not sure off the cuff if the statsmodel API supports this usage.

Also, this may help for the latter:

https://machinelearningmastery.com/make-manual-predictions-arima-models-python/

Thanks for your reply again.

I have been working with the first method you mentioned. It is the correct method that can meet my demand. But it has a very high time spending. Well I test on the stock index data such as DJI.NYSE including 3000+ data. It is very hard for arima method to make a good regression. Maybe stocks data can not be predicted.

The stock market is not predictable:

https://machinelearningmastery.com/faq/single-faq/can-you-help-me-with-machine-learning-for-finance-or-the-stock-market

Hey , I am getting error here doing import series but getting error from csv file side

Note that some of the default arguments are different, so please refer to the documentation for from_csv when changing your function calls

infer_datetime_format=infer_datetime_format)

Traceback (most recent call last):

File “sarima.py”, line 10, in

series = Series.from_csv(‘/home/techkopra/Documents/Sarima_machine-learnig/daily-minimum-temperatures1.csv’, header=None)

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/series.py”, line 3728, in from_csv

result = df.iloc[:, 0]

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/indexing.py”, line 1472, in __getitem__

return self._getitem_tuple(key)

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/indexing.py”, line 2013, in _getitem_tuple

self._has_valid_tuple(tup)

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/indexing.py”, line 222, in _has_valid_tuple

self._validate_key(k, i)

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/indexing.py”, line 1957, in _validate_key

self._validate_integer(key, axis)

File “/home/techkopra/Documents/Sarima_machine-learnig/env/lib/python3.6/site-packages/pandas/core/indexing.py”, line 2009, in _validate_integer

raise IndexError(“single positional indexer is out-of-bounds”)

IndexError: single positional indexer is out-of-bounds

could you support me this error ?

Thanks

I have some suggestions here:

https://machinelearningmastery.com/faq/single-faq/why-does-the-code-in-the-tutorial-not-work-for-me

Hey buddy,

I am getting issue this

Traceback (most recent call last):

File “hello.py”, line 23, in

differenced = difference(X, days_in_year)

File “hello.py”, line 10, in difference

value = dataset[i] – dataset[i – interval]

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

Thanks

Are you using Python 3?

yes

it’s this project run under python 2 env ?

I use Python 3.6.

I expect it will work for Python 2.7.

Why is it required to make the data stationary ? when you the observation for each day from the same day one year before, doesn’t this affect the data and hence the results ?

It greatly simplifies the prediction problem and meets the expectations of the linear model.

Try with/without and compare results!

I used your code to forecast next 365 days. But forecast values before inverse converge to 0.0131662 from 96th step on. That means forecast values after inverse are just last year’s values + 0.0131662. This is almost equivalent to no forecasting at all. In real practice, how do people do forecasting for a longer future time period?

That is a lot of days to forecast!

From what I have seen, forecasting more than a dozen time steps into the future results in too much error to be useful on most problems – it depends on the dataset of course.

So normally how do people use an ARIMA model in the production environment? They only use it to predict next couple data points in the future? Whenever new data points come in, they will use them to update the future prediction? For example, suppose today is 2/1. I use historical data up to 2/1 to predict 2/2 to 2/10. Once 2/2 data comes in, I include 2/2 data into historical data to predict/update the prediction for 2/3 to 2/10 plus 2/11. Is this the correct process to use an ARIMA in deployment?

It can be, it really depends on your production environment.

For example, in some cases, perhaps the coefficients are used directly to make a prediction, e.g. using another language. In other environments, perhaps the model can be used directly.

Also, when it comes to updating the model, I recommend testing different schedules to see what is effective for your specific data.

Hi. How do you do this for multiple time series at the same time? for example df with 50 columns or so

Perhaps one model per time series.

Or use a method like a neural net that can support multiple input variables:

https://machinelearningmastery.com/start-here/#deep_learning_time_series

Hi jason, This tutorial is really awesome…

can you please help me on plotting the graph to compare the predicted and actual value and to find the RMSE score?

You can get started with plots here:

https://machinelearningmastery.com/load-explore-time-series-data-python/

Sir,

Your blogs were really helpful. I felt depth understanding in your blogs only when compared to other. Thank you soo much.

And I have a doubt. Can we detect Anomaly using ARIMA moel ?

Thanks.

No, ARIMA is not really suited to anomaly detection.

“No, ARIMA is not really suited to anomaly detection.” Can you suggest some methods which are suitable for anomaly detection in time series?

I hope to cover this topic in great detail in the future.

Perhaps investigate the problem as an imbalanced classification task?

I have monthly data but some months information is missing ,can i use arima on this type of data.

You can fill in the missing values with a mean/median value.

But what if my data has strong seasonality?

Then the value at the same point in the previous cycle would be better.

Hi,

how can i make future prediction if i have used the following function to make prediction :

for timepoint in range(len(TestData)):

ActualValue = TestData[timepoint]

#forcast value

Prediction = StartARIMAForecasting(Actual, 1,1,1)

print(‘Actual=%f, Predicted=%f’ % (ActualValue, Prediction))

#add it in the list

Predictions.append(Prediction)

Actual.append(ActualValue)

and thanks

You can use model.predict() or model.forecast() as specified in the post.

hi,

please tell why it is not working correctly:

a=[1,2,3,4,1,2,3,4]

da = difference(a)

X=a

forecast=da

forecast

[1, 1, 1, -3, 1, 1, 1]

days_in_year=4

history = [x for x in X]

day = 1

for yhat in forecast:

inverted = inverse_difference(history, yhat, days_in_year)

print(‘Day %d: %f’ % (day, inverted))

history.append(inverted)

day += 1

history

Day 1: 2.000000

Day 2: 3.000000

Day 3: 4.000000

Day 4: 1.000000

Day 5: 3.000000

Day 6: 4.000000

Day 7: 5.000000

why day5 is incorrect?

I have some suggestions here:

https://machinelearningmastery.com/faq/single-faq/can-you-read-review-or-debug-my-code

Hi,

how can i calculate RMSE and other indictors of performance ?

thank you

You can use the sklearn metrics to calculate the error between an array of predictions and an array of expected values:

https://scikit-learn.org/stable/modules/classes.html#sklearn-metrics-metrics

Hi Jason,

Your blog are very helpful. I applied ARIMA by setting the train and test data by ratios (like, 90:10, 80:20, 70:30..) for prediction. i thought RMSE value reduces as the train data increases. but i got the below answer when i predicted for 5 years of data.

Ratio MSE RMSE

90-10 116.18 10.779

80-20 124.336 11.151

70-30 124.004 11.136

60-40 126.268 11.237

50-50 127.793 11.305

40-60 137.029 11.706

30-70 133.29 11.545

So, now i got confused. The RMSE has to reduce as training set increases or RMSE varies? if varies, can you tell me what are the possible reasons for variation?

thank you

Variation in reported error scores is based on the data used to train the model and the interval being predicted.

It is a good idea to summarise the performance of the model using walk-forward validation over a large interval.

hi,thanks for your blog but i need support. when i run code :

def difference(dataset, interval=1):

diff =list()

for i in range(interval, len(dataset)):

value = dataset[i]-dataset[i-interval]

diff.append(value)

return numpy.array(diff)

df = pd.read_csv(‘dataset.csv’,header=None)

X = df.values

day_in_year = 365

differenced = difference(X,day_in_year)

model =ARIMA(differenced,order=(7,0,1))

model_fit=model.fit(disp=0)

print(model_fit.summary())

and

TypeError Traceback (most recent call last)

in

9 X = df.values

10 day_in_year = 365

—> 11 differenced = difference(X,day_in_year)

12

13 model =ARIMA(differenced,order=(7,0,1))

in difference(dataset, interval)

2 diff =list()

3 for i in range(interval, len(dataset)):

—-> 4 value = dataset[i]-dataset[i-interval]

5 diff.append(value)

6 return numpy.array(diff)

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

i don’t know what it’s mean. i run it in python3, can u help me? tks

Sorry to hear that, I have some suggestions here:

https://machinelearningmastery.com/faq/single-faq/why-does-the-code-in-the-tutorial-not-work-for-me

please i want to apply this code to time series data , but i want to make sliding window that take the first five values and predict the six and make sliding to the next ,what should i change to build this model

You can change the order to be something like (5,1,0) and use the forecast() function with the number of steps set to 6.

Hi Jason!

I would like to make a out of sample prediction of the data. However, from what I have seen from your tutorial as well as other posts online, most of the prediction seemed more like a validation of the data that they are already have.

E.g. I have the annual population data from 1950-2019

I split the data into the train data(1950 -1998) and the test data (1998 onwards to 2019).

Of course I start off with creating my model using the sample data, then doing a validation using the test data. But how do I predict the annual population beyond 2019?

Thank you so much!

Good question.

Fit your model on all available data to create a final model. Then use the final model by calling forecast() or predict() for the interval you wish to forecast.

Thank you so much for your prompt response!

Another question. I am actually using auto_arima in python. However, I am a little confused as to how the predict function in auto_arima work. Unlike the predict in ARIMA, there are no start or end parameters. The parameters are (from what I found so far) n_periods. If that is the case, how is the algorithm supposed to know if you are doing a in-sample prediction or a out-sample prediction?

This was how I used it in my code.

test is the test data whereas train is the training data

newforecast is basically the predicted value for the test data. However, I would like to do a out-sample prediction instead.

import pmdarima as pm

for ctry in seadict.keys():

dataa = seadict[ctry]

slicing = int(len(dataa)*0.7)

train = dataa[0:slicing]

test=dataa[slicing:len(dataa)]

mod = pm.auto_arima(train, error_action=’ignore’, suppress_warnings = True)

mod.fit(train)

forecast = mod.predict(n_periods=len(test))

newforecast = pd.Series(forecast, index=test.index)

I am not familiar with that library, sorry.

I have my own implementation here that might help:

https://machinelearningmastery.com/how-to-grid-search-sarima-model-hyperparameters-for-time-series-forecasting-in-python/

Hi how can i install the dataset?

the link just shows the data on webpage

Download the dataset as a .csv file in the same directory as your .py python file.

I have a time series that’s on a monthly cadence but with some months missing. I’d like to fill in the values using an ARIMA model, but I keep getting errors from the “predict” method when I try to specify one of the missing dates using “start=missing_date end=missing_date”. When I try “predict” using “exog = [ missing_date ]” there is no error but what I get back is just the original time series (with gaps) that was used to fit the ARIMA model. I’m starting to wonder whether there is no way to “interpolate” using ARIMA; is that correct?

Filling in missing values with ARIMA is hard, you may have to fit a model that ends prior to each gap and then predict the gap.

Also try the forecast() function, it is much easier.

difference function is doing the difference between current and previous day value not the previous year value. You are describing it as year in the post. Hope i’m correct

Look at how we call the function and pass in 365.

Hi,

Thanks for your tutorials. They are amazing.

I had to make the following changes to make the code work. Notice that had to use index [1] in line 5 and the last line. Ami I doing some thing wrong?

Appreciate if you can point out my error. I am using Anaconda 3.5

# create a differenced series

def difference(dataset, interval=1):

diff = list()

for i in range(interval, len(dataset)):

value = dataset[i][1] – dataset[i – interval][1]

diff.append(value)

return numpy.array(diff)

# invert differenced value

def inverse_difference(history, yhat, interval=1):

return yhat + history[-interval][1]

You’re welcome, thanks for your kind words!

Sorry to hear that, perhaps confirm that you are using Python 3.6+ and that you copied all of the code and data exactly.

Also this might help:

https://machinelearningmastery.com/faq/single-faq/why-does-the-code-in-the-tutorial-not-work-for-me

I think I know where the problem is. It is in the read statement. I am trying figure out a way to read correctly

Great!

A nice yet concise tutorial, Dr. Jason Brownlee!

I have a basic question I still couldn’t get the answer to: What are the components of the output of arima.model.ARIMAResults.forecast()?

The output according to its docs is “Array of out of sample forecasts. A (steps x k_endog) array.” I’m sure endog means the input array used as history for training, and steps is the specified integer parameter. I’m not sure what k_endog means.

Could you please let us know?

Thanks

Thanks!

I believe the forecasted interval and the prediction interval for each point forecast.

When the code is compiled, this error shows.

File “C:/Users/D.T/.spyder-py3/untitled1.py”, line 9, in difference

value = dataset[i] – dataset[i – interval]

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

Please Help !!

Sorry to hear that, this might help:

https://machinelearningmastery.com/faq/single-faq/why-does-the-code-in-the-tutorial-not-work-for-me

The

`end`

argument could not be matched to a location related to the index of the data.’This is what I am getting when I use :

pred = res.predict(start = ‘2014-11-05’, end = ‘2019-02-01’)

How to do out of forecast predictions when we have date as our index

I don’t have an example off the cuff, sorry.

Hi Jason,

Firstly thanks a ton for useful blogs!

I had a doubt in this one:- https://machinelearningmastery.com/make-sample-forecasts-arima-python/

You have used predict function to make out of sample forecasts.

However when i tried it ;-

1) I was only able to run the predict function on start and end indexes as numbers and not dates

2) If i give a number below len(series) (in our case differenced), will i get a forecast of a subset of the training data itself? Meaning, i can easily compare actual/predicted like we do in linear regression?

Because everywhere, you have discussed about out of sample forecasts and not in sample ones.

Thanks,

Abhay

I don’t have examples of forecasting with dates, sorry.

You can predict the train set, but it is better to use walk-forward validation to evaluate a model:

https://machinelearningmastery.com/backtest-machine-learning-models-time-series-forecasting/

i only have daily data for four months in one year and i want to forecast to sales for the coming years. how can i do it. because i see from the difference that you comparing with data of the same period from the previous year which i dont have. How can i forecast with my limited data.

Fit the model on available data and call model.predict().

Perhaps I don’t understand the problem you’re having exactly?

Hello Jason I’m using python 3.7.4

but still there is problem with

TypeError Traceback (most recent call last)

in

16 X = series.values

17 days_in_year = 365

—> 18 differenced = difference(X, days_in_year)

19 # fit model

20 model = ARIMA(differenced, order=(7,0,1))

in difference(dataset, interval)

7 diff = list()

8 for i in range(interval, len(dataset)):

—-> 9 value = dataset[i] – dataset[i – interval]

10 diff.append(value)

11 return numpy.array(diff)

TypeError: unsupported operand type(s) for -: ‘str’ and ‘str’

Your tutorials help me alot and I started my machine learning journey by following youre website and email newsletter.

please help me with this issue I tried all the ways

Sorry to hear that, this will help:

https://machinelearningmastery.com/faq/single-faq/why-does-the-code-in-the-tutorial-not-work-for-me

can we have same functions in RNN ?

Please share if you have post

Yes, you can start here:

https://machinelearningmastery.com/start-here/#deep_learning_time_series

hello~ This post helps me a lot.

But I have a question about the arma model.

I know that the arma model is a linear model, when I use the fit() function to train the model,I have get the parameters,how can I use the learned parameters to predict future values using another time series?

You can fit a separate model for each time series.

hi,

i understand that you defined your differencing and inverse differencing function because you may need those to verify stationarity of the series but why didn’t you use the models differencing feature. i mean wouldnt that be easier? rather than inverting the forecast back manually.

It would be easier. I don’t recall why.

Dear Mr Bronwlee,

thanks a lot for your example and the explanation! It is extremely helpful!

You apply the statsmodel function ARIMA with parameters (p=7,d=0,q=1). Setting the lag-parameter to d=0 makes the ARIMA model effectively become a ARMA model: see https://www.statsmodels.org/dev/_modules/statsmodels/tsa/arima_model.html#ARIMA.

On the other hand you manually generate a stationary time series by your difference-function. This again makes the total example ARIMA again, if I understand correctly.

What is the reason you do not use the build-in functionality of ARIMA of building discrete differences?

If I understand correctly this is done by the following line in the statmodel arima-class: self.endog = np.diff(self.endog, n=d) . What is the advantage of your “difference” function (which imho does the same)?

Kind regards,

Wolfgang

Yes, using the ARIMA directly is better.

I am trying to drill data prep into peoples heads.

Thanks, that clarifies it. Apologies for my misspelling, Mr. Brownlee.

Kind regards,

Wolfgang

You’re welcome.

Did you find that your differential prediction value（model_fit.forcast()） is almost 0, so your final prediction result is only the value of 360 days(or one year) ago?

I don’t recall, sorry. Perhaps explore yourself?

Hi Jason. I am working on a time series problem. My model predicts a straight line, which is very unusual from the test_data.

So, Initially, I decomposed the series using “additive”(visually I can find that there is no seasonality) method and as expected, seasonality is zero and at the same time the value of “residuals” is also zero.

I modeled the series using ARIMA. “model_fit.resid” is “white noise”, which I further verified from ACF plot, mean and variance values.

But still my model predicts a straight line, which is very unusual from the test_data. Could you please help me out.

Perhaps try an alternate model or model configuration?

Perhaps test different data preparation methods prior to model?

Perhaps your problem is not predictable?

This part of the code is throwing error but it has create dataset.csv and validation.csv while i use my dataset

# load dataset

series = read_csv(‘dataset.csv’, header=None)

# seasonal difference

X = series.values

days_in_year = 365

differenced = difference(X, days_in_year)

# fit model

model = ARIMA(differenced, order=(7,0,1))

error as

18 differenced = difference(X, days_in_year)

19 # fit model

—> 20 model = ARIMA(differenced, order=(7,0,1))

21 model_fit = model.fit(disp=0)

22 # print summary of fit model

ValueError: Insufficient degrees of freedom to estimate

You might need to change the configuration of your model to better match your data.

in this example u did the forecast of data that is already present in the data set i.e from 25th dec it is theire in dataset ….how to forecast fro upcoming days???

You can call model.predict() or model.forecast() to predict anything you want with your model.

I have found great comfort in knowing that there are people like you helping everyone around. You truly are an inspiration Sir.

I need your help now, im doing a multistep ARIMA forecast, but its also a rolling forecast. Meaning i want to forecast 7 days ahead but not only once, rather to my 30 validation set. Do you any tutorial that can help

Yes, I have many tutorials on this using walk-forward validation, perhaps start here:

https://machinelearningmastery.com/arima-for-time-series-forecasting-with-python/